问题
If I write like this:
ShellExecute(NULL, "open", "www.google.com", NULL, NULL, SW_SHOWNORMAL);
Everything's okay and is as it has to be.
But I want so that user could enter a link where he wants to go.
std::cout<<"Enter the link: ";
char link;
std::cin>>link;
ShellExecute(NULL, "open", link, NULL, NULL, SW_SHOWNORMAL);
In this case I get an invalid conversion from 'char' to 'const CHAR*
error.
So, is there a way to do this properly?
回答1:
Your code only gets one character in as the link. You need to make link a type able to hold the value of the link and also read stdio in. Making link a std::string will do this but then you need to take care of how it is passed to ShellExecute
std::cout<<"Enter the link: ";
std::string link;
std::cin>>link;
ShellExecute(NULL, "open", link.c_str(), NULL, NULL, SW_SHOWNORMAL);
回答2:
You should declare your input as char*
char *link = new char[2048];
...
delete[] link;
The const char* in ShellExecute is just a promise that it won't change the input. After changing the declaration, everything should work as expected.
来源:https://stackoverflow.com/questions/11168646/c-open-link-with-shellexecute