Subqueries in CakePHP 3?

半世苍凉 提交于 2019-12-20 02:37:25

问题


I have two tables products and product_categories that are associated through a third table, products_categories_products, according to CakePHP BelongsToMany conventions (Edit: these associations are established in ProductsTable.php and ProductCategoriesTable.php). I want to generate a list of product categories, using the image from the best selling products to represent each category.

I can achieve my desired outcome using the following function:

public function findImages(Query $query, array $options) {
    $query->select([
        'ProductCategories.id',
        'ProductCategories.name',
        'ProductCategories__image' => '(SELECT Products.image
        FROM product_categories_products AS ProductCategoriesProducts
        LEFT JOIN products AS Products
        ON ProductCategoriesProducts.product_id = Products.id
        WHERE ProductCategoriesProducts.product_category_id = ProductCategories.id
        ORDER BY Products.turnover DESC
        LIMIT 1)'
    ])->where([
        'ProductCategories.name <>' => 'Unsorted'
    ])->order([
        'ProductCategories.name'    => 'asc'
    ]);
    return $query;
}

Is this acceptable or is there a Cake-ier way to achieve my goal? I couldn't really find anything on the topic of crafting subqueries in CakePHP 3. I just stumbled into the above solution after a couple hours of frustration. Any advice appreciated!


回答1:


Thanks to the link from user ndm_yesterday, I generated the following solution:

public function findImages(Query $query, array $options) {
    $this->hasMany('ProductCategoriesProducts');

    $subquery = $this->ProductCategoriesProducts->find('all')->select([
        'Products.image'
    ])->join([
        [
            'table'     => 'products',
            'alias'     => 'Products',
            'type'      => 'LEFT',
            'conditions'=> [
                'ProductCategoriesProducts.product_id = Products.id'
            ]
        ]
    ])->where([
        'ProductCategoriesProducts.product_category_id = ProductCategories.id'
    ])->order([
        'Products.turnover' => 'DESC'
    ])->limit(1);

    $query->select([
        'ProductCategories.id',
        'ProductCategories.name',
        'ProductCategories__image' => $subquery
    ])->where([
        'ProductCategories.name <>' => 'Unsorted'
    ])->order([
        'ProductCategories.name'    => 'asc'
    ]);

    return $query;
}


来源:https://stackoverflow.com/questions/33884603/subqueries-in-cakephp-3

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!