问题
Lets say I have this class
public class Employee
{
public string FirstName { get; set; }
public string LastName { get; set; }
public bool isActive { get; set; }
}
And use it like this:
List<Employee> Employees = new List<Employee>();
Employees.Add(new Employee { FirstName = "firstname", LastName = "lastname", isActive = true });
List<Employee> EmployeesCopy = new List<Employee>(Employees);
EmployeesCopy[0].isActive = false;
Why does change in isActive
property of EmployeesCopy
also modify property in the original list?
回答1:
Because the new list still contains references to the same employee objects. You can create new ones in a new list by doing something like this:
List<Employee> Employees = new List<Employee>();
Employees.Add(new Employee { FirstName = "firstname", LastName = "lastname", isActive = true });
List<Employee> EmployeesCopy = Employees.Select(x => new Employee(x)).ToList();
public class Employee
{
public string FirstName { get; set; }
public string LastName { get; set; }
public bool isActive { get; set; }
public Employee()
{ }
public Employee(Employee e)
{
FirstName = e.FirstName;
LastName = e.LastName;
isActive = e.isActive;
}
}
回答2:
You're doing a shallow copy, not a deep copy. This means that the new list contains the same objects from the original list.
To do a deep copy, you will need to iterate through your original list and make new Employee
objects for the new list, like this.
private List<Employee> CloneEmployees(List<Employee> original)
{
var newList = new List<Employee>();
foreach (var employee in original)
{
newList.Add(new Employee
{
FirstName = employee.FirstName,
LastName = employee.LastName,
isActive = employee.isActive
});
}
return newList;
}
回答3:
Why does change in the isActive property of EmployeesCopy also modify the original list?|
Because both the list point to the same instance of the Employee object. You need to deep copy your Employee object as well.
回答4:
The copy is a new List
object, but it contains references to the same set of Employee
objects that are in the original list. If you want the Employee
objects in the two lists to be independent, then you have to copy them individually and put the copies into a new list.
回答5:
The copy you create is just a copy of the list. Not a copy of the objects. In other words, Employees[0] == EmployeesCopy[0]
.
回答6:
because by using new List<Employee>(Employees);
will give you the new instance of List but not the objects contained in the list. You should consider cloning of objects contained in the list also , use Binary Serialization to serialize object graph.
来源:https://stackoverflow.com/questions/15408114/why-does-copy-of-the-list-still-change-properties-in-the-original-list-using-c-s