问题
When working on a hierarchical/multilevel/panel dataset, it may be very useful to adopt a package which returns the within- and between-group standard deviations of the available variables.
This is something that with the following data in Stata
can be easily done through the command
xtsum, i(momid)
I made a research, but I cannot find any R
package which can do that..
edit:
Just to fix ideas, an example of hierarchical dataset could be this:
son_id mom_id hispanic mom_smoke son_birthweigth
1 1 1 1 3950
2 1 1 0 3890
3 1 1 0 3990
1 2 0 1 4200
2 2 0 1 4120
1 3 0 0 2975
2 3 0 1 2980
The "multilevel" structure is given by the fact that each mother (higher level) has two or more sons (lower level). Hence, each mother defines a group of observations.
Accordingly, each dataset variable can vary either between and within mothers or only between mothers. birtweigth
varies among mothers, but also within the same mother. Instead, hispanic
is fixed for the same mother.
For example, the within-mother variance of son_birthweigth
is:
# mom1 means
bwt_mean1 <- (3950+3890+3990)/3
bwt_mean2 <- (4200+4120)/2
bwt_mean3 <- (2975+2980)/2
# Within-mother variance for birthweigth
((3950-bwt_mean1)^2 + (3890-bwt_mean1)^2 + (3990-bwt_mean1)^2 +
(4200-bwt_mean2)^2 + (4120-bwt_mean2)^2 +
(2975-bwt_mean3)^2 + (2980-bwt_mean3)^2)/(7-1)
While the between-mother variance is:
# overall mean of birthweigth:
# mean <- sum(data$son_birthweigth)/length(data$son_birthweigth)
mean <- (3950+3890+3990+4200+4120+2975+2980)/7
# within variance:
((bwt_mean1-mean)^2 + (bwt_mean2-mean)^2 + (bwt_mean3-mean)^2)/(3-1)
回答1:
I don't know what your stata command should reproduce, but to answer the second part of question about
hierarchical structure , it is easy to do this with list
.
For example, you define a structure like this:
tree = list(
"var1" = list(
"panel" = list(type ='p',mean = 1,sd=0)
,"cluster" = list(type = 'c',value = c(5,8,10)))
,"var2" = list(
"panel" = list(type ='p',mean = 2,sd=0.5)
,"cluster" = list(type="c",value =c(1,2)))
)
To create this lapply
is convinent to work with list
tree <- lapply(list('var1','var2'),function(x){
ll <- list(panel= list(type ='p',mean = rnorm(1),sd=0), ## I use symbol here not name
cluster= list(type = 'c',value = rnorm(3))) ## R prefer symbols
})
names(tree) <-c('var1','var2')
You can view he structure with str
str(tree)
List of 2
$ var1:List of 2
..$ panel :List of 3
.. ..$ type: chr "p"
.. ..$ mean: num 0.284
.. ..$ sd : num 0
..$ cluster:List of 2
.. ..$ type : chr "c"
.. ..$ value: num [1:3] 0.0722 -0.9413 0.6649
$ var2:List of 2
..$ panel :List of 3
.. ..$ type: chr "p"
.. ..$ mean: num -0.144
.. ..$ sd : num 0
..$ cluster:List of 2
.. ..$ type : chr "c"
.. ..$ value: num [1:3] -0.595 -1.795 -0.439
Edit after OP clarification
I think that package reshape2
is what you want. I will demonstrate this here.
The idea here is in order to do the multilevel analysis we need to reshape the data.
First to divide the variables into two groups :identifier and measured variables. library(reshape2) dat.m <- melt(dat,id.vars=c('son_id','mom_id')) ## other columns are measured
str(dat.m)
'data.frame': 21 obs. of 4 variables:
$ son_id : Factor w/ 3 levels "1","2","3": 1 2 3 1 2 1 2 1 2 3 ...
$ mom_id : Factor w/ 3 levels "1","2","3": 1 1 1 2 2 3 3 1 1 1 ...
$ variable: Factor w/ 3 levels "hispanic","mom_smoke",..: 1 1 1 1 1 1 1 2 2 2 ...
$ value : num 1 1 1 0 0 0 0 1 0 0 ..
Once your have data in "moten" form , you can "cast" to rearrange it in the shape that you want:
# mom1 means for all variable
acast(dat.m,variable~mom_id,mean)
1 2 3
hispanic 1.0000000 0 0.0
mom_smoke 0.3333333 1 0.5
son_birthweigth 3943.3333333 4160 2977.5
# Within-mother variance for birthweigth
acast(dat.m,variable~mom_id,function(x) sum((x-mean(x))^2))
1 2 3
hispanic 0.0000000 0 0.0
mom_smoke 0.6666667 0 0.5
son_birthweigth 5066.6666667 3200 12.5
## overall mean of each variable
acast(dat.m,variable~.,mean)
[,1]
hispanic 0.4285714
mom_smoke 0.5714286
son_birthweigth 3729.2857143
回答2:
I know this question is four years old, but recently I wanted to do the same in R and came up with the following function. It depends on dplyr
and tibble
. Where: df is the dataframe, columns is a numerical vector to subset the dataframe and individuals is the column with the individuals.
xtsumR<-function(df,columns,individuals){
df<-dplyr::arrange_(df,individuals)
panel<-tibble::tibble()
for (i in columns){
v<-df %>% dplyr::group_by_() %>%
dplyr::summarize_(
mean=mean(df[[i]]),
sd=sd(df[[i]]),
min=min(df[[i]]),
max=max(df[[i]])
)
v<-tibble::add_column(v,variacao="overal",.before=-1)
v2<-aggregate(df[[i]],list(df[[individuals]]),"mean")[[2]]
sdB<-sd(v2)
varW<-df[[i]]-rep(v2,each=12) #
varW<-varW+mean(df[[i]])
sdW<-sd(varW)
minB<-min(v2)
maxB<-max(v2)
minW<-min(varW)
maxW<-max(varW)
v<-rbind(v,c("between",NA,sdB,minB,maxB),c("within",NA,sdW,minW,maxW))
panel<-rbind(panel,v)
}
var<-rep(names(df)[columns])
n1<-rep(NA,length(columns))
n2<-rep(NA,length(columns))
var<-c(rbind(var,n1,n1))
panel$var<-var
panel<-panel[c(6,1:5)]
names(panel)<-c("variable","variation","mean","standard.deviation","min","max")
panel[3:6]<-as.numeric(unlist(panel[3:6]))
panel[3:6]<-round(unlist(panel[3:6]),2)
return(panel)
}
来源:https://stackoverflow.com/questions/14165752/between-within-standard-deviations