问题
I have some strings like this
string phoneNumber = "(914) 395-1430";
I would like to strip out the parethenses and the dash, in other word just keep the numeric values.
So the output could look like this
9143951430
How do I get the desired output ?
回答1:
You do any of the following:
Use regular expressions. You can use a regular expression with either
A negative character class that defines the characters that are what you don't want (those characters other than decimal digits):
private static readonly Regex rxNonDigits = new Regex( @"[^\d]+");
In which case, you can do take either of these approaches:
// simply replace the offending substrings with an empty string private string CleanStringOfNonDigits_V1( string s ) { if ( string.IsNullOrEmpty(s) ) return s ; string cleaned = rxNonDigits.Replace(s, "") ; return cleaned ; } // split the string into an array of good substrings // using the bad substrings as the delimiter. Then use // String.Join() to splice things back together. private string CleanStringOfNonDigits_V2( string s ) { if (string.IsNullOrEmpty(s)) return s; string cleaned = String.Join( rxNonDigits.Split(s) ); return cleaned ; }
a positive character set that defines what you do want (decimal digits):
private static Regex rxDigits = new Regex( @"[\d]+") ;
In which case you can do something like this:
private string CleanStringOfNonDigits_V3( string s ) { if ( string.IsNullOrEmpty(s) ) return s ; StringBuilder sb = new StringBuilder() ; for ( Match m = rxDigits.Match(s) ; m.Success ; m = m.NextMatch() ) { sb.Append(m.Value) ; } string cleaned = sb.ToString() ; return cleaned ; }
You're not required to use a regular expression, either.
You could use LINQ directly, since a string is an
IEnumerable<char>
:private string CleanStringOfNonDigits_V4( string s ) { if ( string.IsNullOrEmpty(s) ) return s; string cleaned = new string( s.Where( char.IsDigit ).ToArray() ) ; return cleaned; }
If you're only dealing with western alphabets where the only decimal digits you'll see are ASCII, skipping
char.IsDigit
will likely buy you a little performance:private string CleanStringOfNonDigits_V5( string s ) { if (string.IsNullOrEmpty(s)) return s; string cleaned = new string(s.Where( c => c-'0' < 10 ).ToArray() ) ; return cleaned; }
Finally, you can simply iterate over the string, chucking the digits you don't want, like this:
private string CleanStringOfNonDigits_V6( string s ) { if (string.IsNullOrEmpty(s)) return s; StringBuilder sb = new StringBuilder(s.Length) ; for (int i = 0; i < s.Length; ++i) { char c = s[i]; if ( c < '0' ) continue ; if ( c > '9' ) continue ; sb.Append(s[i]); } string cleaned = sb.ToString(); return cleaned; }
Or this:
private string CleanStringOfNonDigits_V7(string s) { if (string.IsNullOrEmpty(s)) return s; StringBuilder sb = new StringBuilder(s); int j = 0 ; int i = 0 ; while ( i < sb.Length ) { bool isDigit = char.IsDigit( sb[i] ) ; if ( isDigit ) { sb[j++] = sb[i++]; } else { ++i ; } } sb.Length = j; string cleaned = sb.ToString(); return cleaned; }
From a standpoint of clarity and cleanness of code, the version 1 is what you want. It's hard to beat a one liner.
If performance matters, my suspicion is that the version 7, the last version, is the winner. It creates one temporary — a StringBuilder()
and does the transformation in-place within the StringBuilder's in-place buffer.
The other options all do more work.
回答2:
use reg expression
string result = Regex.Replace(phoneNumber, @"[^\d]", "");
回答3:
try something like this
return new String(input.Where(Char.IsDigit).ToArray());
回答4:
string phoneNumber = "(914) 395-1430";
var numbers = String.Join("", phoneNumber.Where(char.IsDigit));
回答5:
He means everything @gleng
Regex rgx = new Regex(@"\D");
str = rgx.Replace(str, "");
回答6:
Instead of a regular expression, you can use a LINQ method:
phoneNumber = String.Concat(phoneNumber.Where(c => c >= '0' && c <= '9'));
or:
phoneNumber = String.Concat(phoneNumber.Where(Char.IsDigit));
来源:https://stackoverflow.com/questions/19167669/keep-only-numeric-value-from-a-string