d3 js - loading json without a http get

Question

I am learning d3. There are certain ways of loading the data in d3 js. But all of them seem to make a HTTP GET. In my scenario, I already have the json data in a string. How can I use this string instead of making another http request? I tried to look for documentation for this but found none.

This works:

d3.json("/path/flare.json", function(json) {
    //rendering logic here
}

Now, if I have:

//assume this json comes from a server (on SAME DOMAIN)
var myjson = '{"name": "flare","children": [{"name": "analytics","children": [{"name": "cluster","children": [{"name": "MergeEdge", "size": 10 }]}]}]}'; 

How do I use already computed 'myjson' in d3 & avoid a async call to server? Thanks.

Answer 1

Simply replace d3.json call with

json = JSON.parse( myjson );

IE:

var myjson = '{"name": "flare","children": [{"name": "analytics","children": [{"name": "cluster","children": [{"name": "MergeEdge", "size": 10 }]}]}]}';

// d3.json("/path/flare.json", function(json) { #delete this line

    json = JSON.parse( myjson ); //add this line

    //rendering logic here

//} #delete this line

UPDATE 09/2013

Original code has changed. So varname json should be root:

// d3.json("flare.json", function(error, root) { #delete this line

    root = JSON.parse( myjson ); //add this line

    //rendering logic here

//} #delete this line

Answer 2

According to this example:

http://phrogz.net/JS/d3-playground/#StockPrice_HTML

Here they are storing the graph data within the variable $data, and setting it via the .data($data) function.

I'd apply this method to whatever graph you are using.

Answer 3

The answer from chumkiu worked great for me but needed a couple of tweaks - in the latest version of the d3 bubble chart, you need to define root rather than json, as in

 root = JSON.parse( myjson );

Alternatively, you could replace "root" with "json" in the rest of the code of course. :-)

For anyone coming to this answer with questions about d3 node-link trees that utilize local data sets, this answer worked great for me - many thanks to the contributors on this page.