SQL Server: Two-level GROUP BY with XML output

问题

I have a table of hierarchical data that I am trying to select as a single, grouped XML value:

Columns: Id, Type, SubType, SubSubType

Sample data:

Id  Type                    Subtype                    SubSubType
1   Product Documentation   Brochures                  Functional Brochures
2   Product Documentation   Brochures                  Fliers
3   Product Documentation   Data Sheets and Catalogs   Data Sheets
4   Product Documentation   Data Sheets and Catalogs   Catalogs
5   Other Documentation     Other classification       User Guides

For the above data, I would like to output the following xml:

<AllTypes>
    <Type name="Product Documentation">
        <SubType name="Brochures">
            <SubSubType name="Functional Brochures"/>
            <SubSubType name="Fliers"/>
        </SubType>
        <SubType name="Data Sheets and Catalogs">
            <SubSubType name="Data Sheets"/>
            <SubSubType name="Catalogs"/>
        </SubType>
    </Type>
    <Type name="Other Documentation">
        <SubType name="Other classification">
            <SubSubType name="User Guides"/>
        </SubType>
    </Type>
</AllTypes>

i.e. a single xml structure containing all rows from the above table, grouped by the first column (Type), and further grouped by the second column (SubType).

回答1:

declare @T table
(
  ID int,
  Type varchar(30),
  SubType varchar(30),
  SubSubType varchar(30)
)

insert into @T values
(1, 'Product Documentation', 'Brochures',                'Functional Brochures'),
(2, 'Product Documentation', 'Brochures',                'Fliers'),
(3, 'Product Documentation', 'Data Sheets and Catalogs', 'Data Sheets'),
(4, 'Product Documentation', 'Data Sheets and Catalogs', 'Catalogs'),
(5, 'Other Documentation',   'Other classification',     'User Guides')

select T1.Type as '@Name',
       (
       select T2.SubType as '@Name',
              (
              select T3.SubSubType as '@Name'
              from @T as T3
              where T3.SubType = T2.SubType and
                    T3.Type = T1.Type
              for xml path('SubSubType'), type
              )
       from @T as T2
       where T2.Type = T1.Type
       group by T2.SubType
       for xml path('SubType'), type
       )
from @T as T1
group by Type
for xml path('Type'), root('AllTypes')

回答2:

select
   T1.Type as name,
   (
     select
        T2.SubType as name,
        (
          select T3.SubSubType as name
          from Table1 as T3
          where T3.Type = T1.Type and T3.SubType = T2.SubType
          for xml raw('SubSubType'), type
        )
     from (select distinct Type, SubType  from Table1) as T2
     where T1.Type = T2.Type
     for xml raw('SubType'), type
   )
from (select distinct Type from Table1) as T1
for xml raw('Type'), root('AllTypes')

sql fiddle demo

来源：https://stackoverflow.com/questions/18132039/sql-server-two-level-group-by-with-xml-output

标签

sql

sql-server-2008

sqlxml