Remove empty strings from array while keeping record Without Loop?

情到浓时终转凉″ 提交于 2019-11-27 06:13:34
var arr = ["I", "am", "", "still", "here", "", "man"]
// arr = ["I", "am", "", "still", "here", "", "man"]
arr = arr.filter(Boolean)
// arr = ["I", "am", "still", "here", "man"]

filter documentation


// arr = ["I", "am", "", "still", "here", "", "man"]
arr = arr.filter(v=>v!='');
// arr = ["I", "am", "still", "here", "man"]

Arrow functions documentation

var newArray = oldArray.filter(function(v){return v!==''});

PLEASE NOTE: The documentation says:

filter is a JavaScript extension to the ECMA-262 standard; as such it may not be present in other implementations of the standard. You can work around this by inserting the following code at the beginning of your scripts, allowing use of filter in ECMA-262 implementations which do not natively support it. This algorithm is exactly the one specified in ECMA-262, 5th edition, assuming that fn.call evaluates to the original value of Function.prototype.call, and that Array.prototype.push has its original value.

So, to avoid some heartache, you may have to add this code to your script At the beginning.

if (!Array.prototype.filter) {
  Array.prototype.filter = function (fn, context) {
    var i,
        value,
        result = [],
        length;
        if (!this || typeof fn !== 'function' || (fn instanceof RegExp)) {
          throw new TypeError();
        }
        length = this.length;
        for (i = 0; i < length; i++) {
          if (this.hasOwnProperty(i)) {
            value = this[i];
            if (fn.call(context, value, i, this)) {
              result.push(value);
            }
          }
        }
    return result;
  };
}
arr = arr.filter(v => v);

as returned v is implicity converted to truthy

sansid1983

If are using jQuery, grep may be useful:


var arr = [ a, b, c, , e, f, , g, h ];

arr = jQuery.grep(arr, function(n){ return (n); });

arr is now [ a, b, c, d, e, f, g];

i.e we need to take multiple email addresses separated by comma, spaces or newline as below.

    var emails = EmailText.replace(","," ").replace("\n"," ").replace(" ","").split(" ");
    for(var i in emails)
        emails[i] = emails[i].replace(/(\r\n|\n|\r)/gm,"");

    emails.filter(Boolean);
    console.log(emails);
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!