问题
I want to sort a string in JAVA alphabetically, as follows Capital letter and lowercase letter followed AaBbCcDdEeFfGg. for example if I put AbaC return me AabC thanks!!
回答1:
You can do this using Arrays.sort
, if you put the characters into an array first. (It must be an array of Character
objects rather than char
primitives, in order to use a custom case-insensitive comparator.)
// put the characters into an array
Character[] chars = new Character[str.length()];
for (int i = 0; i < chars.length; i++)
chars[i] = str.charAt(i);
// sort the array
Arrays.sort(chars, new Comparator<Character>() {
public int compare(Character c1, Character c2) {
int cmp = Character.compare(
Character.toLowerCase(c1.charValue()),
Character.toLowerCase(c2.charValue())
);
if (cmp != 0) return cmp;
return Character.compare(c1.charValue(), c2.charValue());
}
});
// rebuild the string
StringBuilder sb = new StringBuilder(chars.length);
for (char c : chars) sb.append(c);
str = sb.toString();
回答2:
You may try to look for Collections.sort and then try like this:-
Collections.sort(caps, String.CASE_INSENSITIVE_ORDER);
Something like this:-
private static Comparator<String> ALPHA_ORDER = new Comparator<String>() {
public int compare(String str1, String str2) {
int x = String.CASE_INSENSITIVE_ORDER.compare(str1, str2);
if (x== 0) {
x= str1.compareTo(str2);
}
return x;
}
};
Collections.sort(list, ALPHA_ORDER);
EDIT:-
For sorting alphabetically in a string try like this:-
Collator col = Collator.getInstance(new Locale("en", "EN"));
String s = "AbaC";
String[] s1= s.split("");
Arrays.sort(s1, col);
String sorted = "";
for (int i = 0; i < s1.length; i++)
{
sorted += s1[i];
}
System.out.println(sorted);
回答3:
Turn the String into a character array, then compare the int values of each character in your sort.
Methods needed:
String.toCharArray();
来源:https://stackoverflow.com/questions/19468122/how-to-sort-a-string-alphabetically-java