问题
I'm learning scala and mongodb at present and using the play! framework, so I'm making all sorts of mistakes as I get my head around things. Currently I have a scala object that returns a list of database objects returned from a mongodb query via casbah as follows;
object Alerts {
def list() : List[DBObject]= {
val collection = MongoDatabase.collection;
val query = MongoDBObject.empty
val order = MongoDBObject("Issue Time:" -> -1)
val list = collection.find(query).sort(order).toList
list
}
... }
Elsewhere in my code I wish to output the List of objects in Json - so I have;
val currentAlerts = Alerts.list()
What I'd like to write is something like;
val resultingJson = currentAlerts.toJson
But when I do this, I understandably get the following error;
value toJson is not a member of List[com.mongodb.casbah.Imports.DBObject]
My question is - what's the right way to convert a List of com.mongodb.casbah.Imports.DBObject into Json for output?
EDIT:
For clarity, what I really want to do is the equivalent of
val listInJson = collection.find(query).sort(order).toJson
In the same way that I CAN write
val listAsString = collection.find(query).sort(order).toString
回答1:
You can try
com.mongodb.util.JSON.serialize(Alerts.list())
This should return a JSON array with your Alerts
回答2:
I have the following
def service() = Action {
// connect
val collection = MongoConnection()("someDB")("someCollection")
// simply convert the result to a string, separating items with a comma
// this string goes inside an "array", and it's ready to hit the road
val json = "[%s]".format(
collection.find(someQuery).toList.mkString(",")
)
Ok(json).as("application/json")
}
回答3:
I have what is a horrid solution as follows;
val currentAlerts = Alerts.list()
var jsonList : List[JsValue] = Nil
// Iterate over the DBObjects and use to String to convert each to JSON
// and then parse that back into the list so we can use toJson on it later.
// MAD, but works.
for (dbObject <- currentAlerts) {
jsonList ::= Json.parse(dbObject.toString)
}
val result = Json.toJson(jsonList)
Ok(result).as("application/json")
There must surely be a better way?
来源:https://stackoverflow.com/questions/11987071/how-to-convert-casbah-mongodb-list-to-json-in-scala-play