How do I Handle Ties When Ranking Results in MySQL?

问题

How does one handle ties when ranking results in a mysql query? I've simplified the table names and columns in this example, but it should illustrate my problem:

SET @rank=0;

   SELECT student_names.students, 
          @rank := @rank +1 AS rank, 
          scores.grades
     FROM student_names  
LEFT JOIN scores ON student_names.students = scores.students
 ORDER BY scores.grades DESC

So imagine the the above query produces:

Students  Rank  Grades
=======================
Al         1     90
Amy        2     90
George     3     78
Bob        4     73
Mary       5     NULL
William    6     NULL

Even though Al and Amy have the same grade, one is ranked higher than the other. Amy got ripped-off. How can I make it so that Amy and Al have the same ranking, so that they both have a rank of 1. Also, William and Mary didn't take the test. They bagged class and were smoking in the boy's room. They should be tied for last place.

The correct ranking should be:

Students  Rank  Grades
========================
Al         1     90
Amy        1     90
George     2     78
Bob        3     73
Mary       4     NULL
William    4     NULL

If anyone has any advice, please let me know.

回答1:

EDIT: This is MySQL 4.1+ supported

Use:

   SELECT st.name,
          sc.grades,
          CASE 
            WHEN @grade = COALESCE(sc.grades, 0) THEN @rownum 
            ELSE @rownum := @rownum + 1 
          END AS rank,
          @grade := COALESCE(sc.grades, 0)
     FROM STUDENTS st
LEFT JOIN SCORES sc ON sc.student_id = st.id
     JOIN (SELECT @rownum := 0, @grade := NULL) r
 ORDER BY sc.grades DESC

You can use a cross join (in MySQL, an INNER JOIN without any criteria) to declare and use a variable without using a separate SET statement.

You need the COALESCE to properly handle the NULLs.

回答2:

Sounds like a middleware rule that would be better expressed in code that sat between the database and the client.

If that's not possible, I'd recommend a stored procedure in MySQL to run the query as you wrote it and then modify the results using a cursor and an array.

来源：https://stackoverflow.com/questions/2474390/how-do-i-handle-ties-when-ranking-results-in-mysql

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