问题
I have a 100 lines, 3 years old python scraper that now bug. Starting lines are:
import urllib, re, os, sys, time # line 1: import modules
os.chdir(os.path.dirname(sys.argv[0])) # line 2: all works in script's folder > relative address
# (rest of my script here!)
When run,
$cd /my/folder/
$python script.py
I receive the error:
python script.py
Traceback (most recent call last):
File "script.py", line 2, in <module>
os.chdir(os.path.dirname(sys.argv[0]))
OSError: [Errno 2] No such file or directory: ''
How should I read this error and what to do ?
回答1:
Have you noticed that you don't get the error if you run
python ./script.py
instead of
python script.py
This is because sys.argv[0]
will read ./script.py
in the former case, which gives os.path.dirname
something to work with. When you don't specify a path, sys.argv[0]
reads simply script.py
, and os.path.dirname
cannot determine a path.
回答2:
I had this error because I was providing a string of arguments to subprocess.call
instead of an array of arguments. To prevent this, use shlex.split
:
import shlex, subprocess
command_line = "ls -a"
args = shlex.split(command_line)
p = subprocess.Popen(args)
回答3:
Use os.path.abspath()
:
os.chdir(os.path.dirname(os.path.abspath(sys.argv[0])))
sys.argv[0]
in your case is just a script name, no directory, so os.path.dirname()
returns an empty string.
os.path.abspath() turns that into a proper absolute path with directory name.
来源:https://stackoverflow.com/questions/15725273/python-oserror-errno-2-no-such-file-or-directory