问题
Based on this question which was closed rather quickly:
Trying to create a program to read a users input then break the array into seperate words are my pointers all valid?
Rather than closing I think some extra work could have gone into helping the OP to clarify the question.
The Question:
I want to tokenize user input and store the tokens into an array of words.
I want to use punctuation (.,-) as delimiter and thus removed it from the token stream.
In C I would use strtok() to break an array into tokens and then manually build an array.
Like this:
The main Function:
char **findwords(char *str);
int main()
{
int test;
char words[100]; //an array of chars to hold the string given by the user
char **word; //pointer to a list of words
int index = 0; //index of the current word we are printing
char c;
cout << "die monster !";
//a loop to place the charecters that the user put in into the array
do
{
c = getchar();
words[index] = c;
}
while (words[index] != '\n');
word = findwords(words);
while (word[index] != 0) //loop through the list of words until the end of the list
{
printf("%s\n", word[index]); // while the words are going through the list print them out
index ++; //move on to the next word
}
//free it from the list since it was dynamically allocated
free(word);
cin >> test;
return 0;
}
The line tokenizer:
char **findwords(char *str)
{
int size = 20; //original size of the list
char *newword; //pointer to the new word from strok
int index = 0; //our current location in words
char **words = (char **)malloc(sizeof(char *) * (size +1)); //this is the actual list of words
/* Get the initial word, and pass in the original string we want strtok() *
* to work on. Here, we are seperating words based on spaces, commas, *
* periods, and dashes. IE, if they are found, a new word is created. */
newword = strtok(str, " ,.-");
while (newword != 0) //create a loop that goes through the string until it gets to the end
{
if (index == size)
{
//if the string is larger than the array increase the maximum size of the array
size += 10;
//resize the array
char **words = (char **)malloc(sizeof(char *) * (size +1));
}
//asign words to its proper value
words[index] = newword;
//get the next word in the string
newword = strtok(0, " ,.-");
//increment the index to get to the next word
++index;
}
words[index] = 0;
return words;
}
Any comments on the above code would be appreciated.
But, additionally, what is the best technique for achieving this goal in C++?
回答1:
Have a look at boost tokenizer for something that's much better in a C++ context than strtok().
回答2:
Already covered by a lot of questions is how to tokenize a stream in C++.
Example: How to read a file and get words in C++
But what is harder to find is how get the same functionality as strtok():
Basically strtok() allows you to split the string on a whole bunch of user defined characters, while the C++ stream only allows you to use white space as a separator. Fortunately the definition of white space is defined by the locale so we can modify the locale to treat other characters as space and this will then allow us to tokenize the stream in a more natural fashion.
#include <locale>
#include <string>
#include <sstream>
#include <iostream>
// This is my facet that will treat the ,.- as space characters and thus ignore them.
class WordSplitterFacet: public std::ctype<char>
{
public:
typedef std::ctype<char> base;
typedef base::char_type char_type;
WordSplitterFacet(std::locale const& l)
: base(table)
{
std::ctype<char> const& defaultCType = std::use_facet<std::ctype<char> >(l);
// Copy the default value from the provided locale
static char data[256];
for(int loop = 0;loop < 256;++loop) { data[loop] = loop;}
defaultCType.is(data, data+256, table);
// Modifications to default to include extra space types.
table[','] |= base::space;
table['.'] |= base::space;
table['-'] |= base::space;
}
private:
base::mask table[256];
};
We can then use this facet in a local like this:
std::ctype<char>* wordSplitter(new WordSplitterFacet(std::locale()));
<stream>.imbue(std::locale(std::locale(), wordSplitter));
The next part of your question is how would I store these words in an array. Well, in C++ you would not. You would delegate this functionality to the std::vector/std::string. By reading your code you will see that your code is doing two major things in the same part of the code.
- It is managing memory.
- It is tokenizing the data.
There is basic principle Separation of Concerns where your code should only try and do one of two things. It should either do resource management (memory management in this case) or it should do business logic (tokenization of the data). By separating these into different parts of the code you make the code more generally easier to use and easier to write. Fortunately in this example all the resource management is already done by the std::vector/std::string thus allowing us to concentrate on the business logic.
As has been shown many times the easy way to tokenize a stream is using operator >> and a string. This will break the stream into words. You can then use iterators to automatically loop across the stream tokenizing the stream.
std::vector<std::string> data;
for(std::istream_iterator<std::string> loop(<stream>); loop != std::istream_iterator<std::string>(); ++loop)
{
// In here loop is an iterator that has tokenized the stream using the
// operator >> (which for std::string reads one space separated word.
data.push_back(*loop);
}
If we combine this with some standard algorithms to simplify the code.
std::copy(std::istream_iterator<std::string>(<stream>), std::istream_iterator<std::string>(), std::back_inserter(data));
Now combining all the above into a single application
int main()
{
// Create the facet.
std::ctype<char>* wordSplitter(new WordSplitterFacet(std::locale()));
// Here I am using a string stream.
// But any stream can be used. Note you must imbue a stream before it is used.
// Otherwise the imbue() will silently fail.
std::stringstream teststr;
teststr.imbue(std::locale(std::locale(), wordSplitter));
// Now that it is imbued we can use it.
// If this was a file stream then you could open it here.
teststr << "This, stri,plop";
cout << "die monster !";
std::vector<std::string> data;
std::copy(std::istream_iterator<std::string>(teststr), std::istream_iterator<std::string>(), std::back_inserter(data));
// Copy the array to cout one word per line
std::copy(data.begin(), data.end(), std::ostream_iterator<std::string>(std::cout, "\n"));
}
来源：https://stackoverflow.com/questions/6154204/how-to-tokenize-words-classifying-punctuation-as-space