How can I understand if UIApplication is going to open link in Safari app?

问题

I'm developing a browser. I need to open new browser windows in the same WKWebView instance, but also I need to be able opening links in Appstore application.

- (void)webView:(WKWebView *)webView
decidePolicyForNavigationAction:(WKNavigationAction *)navigationAction
decisionHandler:(void (^)(WKNavigationActionPolicy))decisionHandler {
    if (navigationAction.targetFrame == nil) {
        NSURL *url = navigationAction.request.URL;

        UIApplication *app = [UIApplication sharedApplication];
        if ([app canOpenURL:url]) {
            [app openURL:url];
        }
    }
    decisionHandler(WKNavigationActionPolicyAllow);
}

#pragma mark - WKUIDelegate

- (WKWebView *)webView:(WKWebView *)webView createWebViewWithConfiguration:(WKWebViewConfiguration *)configuration
   forNavigationAction:(WKNavigationAction *)navigationAction windowFeatures:(WKWindowFeatures *)windowFeatures {
    if (!navigationAction.targetFrame.isMainFrame) {
        [webView loadRequest:navigationAction.request];
    }
    return nil;
}

the problem is that it opens all new windows in Safari app. How can I understand if UIApplication is going to open link in Safari app?

回答1:

Well, basically, you can´t distinguish this, as App Store links could be https:// links.

Example Link: https://itunes.apple.com/de/app/myLeetApp/id313370815?mt=8

Apple suggests to just use openURL: as you´re doing above. See https://developer.apple.com/library/ios/qa/qa1629/_index.html

If you really really want to distinguish them and do something more fancy (e.g. using StoreKit like this: Possible to show a "in App Store modal" in iOS 6?), you´ve got no other option than to parse every link with a regex like so:

import UIKit

let url = "https://itunes.apple.com/de/app/myLeetApp/id313370815?mt=8"
if url.rangeOfString("itunes.apple.com") != nil {
    let pattern = "^https?:\\/\\/itunes\\.apple\\.com\\/.*id([0-9]*).*$"
    if let regex = NSRegularExpression(pattern: pattern, options: .CaseInsensitive, error: nil) {
        let extractedAppID = regex.stringByReplacingMatchesInString(url, options: nil, range: NSMakeRange(0, countElements(url)), withTemplate: "$1")
    }
}

With the extractedAppID you then can open the SKStoreProductViewController etc.

来源：https://stackoverflow.com/questions/29056854/how-can-i-understand-if-uiapplication-is-going-to-open-link-in-safari-app

标签

ios

iphone

safari

mobile-safari

wkwebview