问题
I have this C++ program with the following general structure
1st while (condition A == true)
//some code for 1st loop
2nd while (condition B == true)
//some code for 2nd loop
try
//some code for try
catch
//condition B == false (supposed to leave 2nd loop and go back to first loop)
I want it to get out of 2nd loop when there's an exception and go back to 1st loop until condition B is tue again. As described above it doesn't work as I expect. What seems to be happening is that code gets stuck in catch
and never leaves it.
How can I arrange it to make it work as I need?
Note: condition A is never false.
回答1:
add the break keyword to the catch
Also notice that you have b == false; That is checking that b is equal to false, not setting b = false.
回答2:
bool flag1 = true, flag2 = true;
while (flag1)
{
// some work so that flag2 == true
while (flag2)
{
try
{
}
catch (...) // any exception happens
{
break;
}
}
}
回答3:
1st while (condition A == true)
//some code for 1st loop
2nd while (condition B == true)
//some code for 2nd loop
try
//some code for try
catch
{
//condition B == false (supposed to leave 2nd loop and go back to first loop)
break ;
}
Notice: Please do not use, even in examples, things like condition A == true
. It is better to use while (condition A)
.
回答4:
You can call break within the catch block to escape the second loop:
void foo(void) {
bool A(true);
while (A) {
bool B(doSomething());
while (B) {
try {
B = doSomethingElseThatMayThrow();
} catch (...) {
break;
}
}
}
}
Alternatively, you could place the second loop inside the try block:
void foo(void) {
bool A(true);
while (A) {
bool B(doSomething());
try {
while (B) {
B = doSomethingElseThatMayThrow();
}
} catch (...) {}
}
}
来源:https://stackoverflow.com/questions/12222947/c-try-catch-inside-loop