问题
While I solve an algorithm question, My solution couldn't get passed because of time issue.
But I realized that the only difference between passed one and mine was
bag.lower_bound(jewerly[i].first) != bag.end() //passed lower_bound(bag.begin(), bag.end(), jewerly[i].first) != bag.end() //failed
I've already checked it with clock()
and It was obviously slower than the other one.
what makes the difference between the two codes?
#include <cstdio>
#include <set>
#include <algorithm>
using namespace std;
const int MAXN = 300100;
bool cmp(pair<int, int> a, pair<int, int> b)
{
if(a.second != b.second)
return a.second > b.second;
return a.first < b.first;
}
pair<int, int> jewerly[MAXN];
multiset<int> bag;
int main()
{
int N, K, M;
scanf("%d%d", &N, &K);
int w, p;
for(int i = 0; i<N; i++)
{
scanf("%d%d", &w, &p);
jewerly[i] = {w, p};
}
for(int i = 0; i<K; i++)
{
scanf("%d", &M);
bag.insert(M);
}
sort(jewerly, jewerly+N, cmp);
clock_t begin = clock();
long long sum = 0;
for(int i = 0; i<N; i++) // #1
{
if( bag.empty() ) break;
if( lower_bound(bag.begin(), bag.end(), jewerly[i].first) != bag.end())
{
sum += jewerly[i].second;
bag.erase(bag.lower_bound(jewerly[i].first));
}
}
/*
for(int i = 0; i<N; i++) //#2
{
if( bag.empty() ) break;
if( bag.lower_bound(jewerly[i].first) != bag.end())
{
sum += jewerly[i].second;
bag.erase(bag.lower_bound(jewerly[i].first));
}
}
*/
clock_t end = clock();
printf("%lf\n", double(end-begin));
}
Test Input 10 8 1 65 5 23 1 30 9 40 3 50 2 90 5 30 5 30 7 80 2 99 10 15 12 5 3 5 2 2
回答1:
std::lower_bound
has no access to internal structure of std::multiset
. It is not O(log N) because iterators of std::multiset
are not random-access (and you can't possibly implement it for not random-access iterator faster then in Theta(N))
std::multiset::lower_bound
does have access to structure of a tree and can be easily implemented with complexity O(tree height) which is O(log N)
来源:https://stackoverflow.com/questions/34922113/why-two-seemingly-lower-bound-same-method-has-different-processing-time