Validate UniqueEntity for One-To-Many, Unidirectional with Join Table [Symfony2]

三世轮回 提交于 2019-12-12 18:14:00

问题


I have 2 mapped entities,

Box

class Box{
    //[...]
    /**
     * @ORM\ManyToMany(targetEntity="Candy", cascade={"remove"})
     * @ORM\OrderBy({"power" = "DESC"})
     * @ORM\JoinTable(name="box_candies",
     *      joinColumns={@ORM\JoinColumn(name="box_id", referencedColumnName="id")},
     *      inverseJoinColumns={@ORM\JoinColumn(name="candy_id", referencedColumnName="id", unique=true)}
     *      )
     */
    private $candies;
}

And Candy

class Candy
{
    /**
     * @var integer
     *
     * @ORM\Column(name="id", type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    private $id;

    /**
     * @var string
     *
     * @ORM\Column(name="name", type="string", length=255)
     */
    private $name;
    //[...]
}

As you can see, this is One-To-Many, Unidirectional with Join Table association. Box can "store" candies, but Candy knows nothing about Box (where is).

Now I have page where I can make candy and there is form and standard isValid() and after that:

$box->addCandy($candy);
$entity_manager->persist($candy);
$entity_manager->persist($box);
$entity_manager->flush();

Now, where is my problem?

I would like to Box can store only unique candies (by name), that means Box can store Candy objects with names "Choco" and "Orange" but can't "Mayonnaise" and "Mayonnaise"

When making candy i can't validate with UniqueEntity constraint because the candy does not know about the box. I thought about Callback validator for Box or create own Constraint but i think it's better to ask:

How should I do it?


回答1:


Answer is late but it may help someone so this is solution I implemented:

In my case I can create Candy only in one place via form so finally I decided to create additional special validation for that case in my controller/service.

Simply speaking I made code checking the name in my own way and when it's invalid, form just trow Error to prevent creation. I want to emphasize that this is a little dirty solution and also it is not scalable because you have to remember always to add it in correct place if you create Candy in other places.

    // special unique name validation
    $candy_name = $form->get('name')->getData();
    if($candy_name){
        $found_candy = $box->getCandyByName($candy_name);
        if($found_candy){
            $error = new FormError( $this->get('translator')->trans("candy.name.exist", array(), "validators") );
            $form->get('name')->addError($error);
        }
    }

Anyway it worked but depending on your case, Callback can be way better solution or even simple UniqueEntity constraint.



来源:https://stackoverflow.com/questions/34523032/validate-uniqueentity-for-one-to-many-unidirectional-with-join-table-symfony2

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!