问题
How do you add extra types to c11 _Generic Functions?
Do you have to #undef/re-#define it?(if so would the following work) or is there a nicer way?
#define to_str(X) _Generic((X), \
long double: ld_str, \
double: d_str, \
float: f_str, \
)(X)
#undef to_str
#define to_str(X) _Generic((X), \
long double: ld_str, \
double: d_str, \
float: f_str, \
int: i_str, \
)(X)
回答1:
I am not sure that I understand your question completely. You mean that you have a type generic macro that is given by some library and you want to amend it with a new type of your own?
What you always could do is to give it another name and use the default case to obtain the provided behavior:
#define to_str2(X) _Generic((X), default: to_str(X), int: i_str(X))
Edit:
This will not work perfectly because you'd have to put the function argument evaluation inside the _Generic
. This means in particular that the type of X
has to be compatible with all branches of the nested generic expressions.
It would be easier if the library in question had a macro that would just return the function itself, without the (X)
, say to_strGen
, and that never would evaluate X
. Then you could do
#define to_str2Gen(X) _Generic((X), default: to_strGen(X), int: i_str)
#define to_str2(X) to_str2Gen(X)(X)
回答2:
If it's your code, you would have to #undef
it and re#define
it, yes. There's no way to extend a type-generic expression (AFAIK).
If it's not your code I'd introduce a second expression with the extension like Jens suggested.
来源:https://stackoverflow.com/questions/9734982/c11-generic-adding-types