问题
I need to create a matrix in TensorFlow to store some values. The trick is the matrix has to support dynamic shape.
I am trying to do the same I would do in numpy:
myVar = tf.Variable(tf.zeros((x,y), validate_shape=False)
where x=(?)
and y=2
. But this does not work because zeros does not support 'partially known TensorShape', so, How should I do this in TensorFlow?
回答1:
1) You could use tf.fill(dims, value=0.0) which works with dynamic shapes.
2) You could use a placeholder for the variable dimension, like e.g.:
m = tf.placeholder(tf.int32, shape=[])
x = tf.zeros(shape=[m])
with tf.Session() as sess:
print(sess.run(x, feed_dict={m: 5}))
回答2:
If you know the shape out of the session, this could help.
import tensorflow as tf
import numpy as np
v = tf.Variable([], validate_shape=False)
with tf.Session() as sess:
sess.run(tf.global_variables_initializer())
print(sess.run(v, feed_dict={v: np.zeros((3,4))}))
print(sess.run(v, feed_dict={v: np.zeros((2,2))}))
来源:https://stackoverflow.com/questions/43263017/variables-with-dynamic-shape-tensorflow