How to get the line numbers of PHP source code executed in more robust way [duplicate]

问题

This question already has answers here:

What is the difference between single-quoted and double-quoted strings in PHP? (11 answers)

php replace $variable in string with the content of $variable (8 answers)

Closed 10 days ago.

I'm trying to get the line numbers of PHP source code implemented at that run time. I used __LINE__ function which return the line number that implemented based on the condition that I gave. I try to put most of the senario of PHP source. However, the function still missed some issue or not working smoothly for all PHP senario syntax. The following example shows what I'm trying to get, and the result I achieved:

(example.php)

<?php  ;      
$a = "Hello World! ";  
$b = "Welcome ";  
if(isset($a)) {
   echo true;   }
if(isset($b)) {
   echo true;   }
else {        
   echo false; 
}

?>

Then when I run my testing code as following:

(test.php)

$file = file_get_contents("example.php");
$lines = explode("\n", $file);
$start = ' $total = NULL;  ';
$append = '  $total = $total . __LINE__ . " - " ; ';
$append2 = '  echo $total; ';
$check_php = 0;

foreach ($lines as $key => &$value) {

if(strpos($value, "<?php") !== false){
    $check_php = 1;
    $value = $value.$start.$append;
}

if(strpos($value, "?>") !== false){
       $value = $append2.$value ;
          $check_php = 0;
}


if($check_php === 1)
{
    if($value == " " OR  empty($value) )
    {

    }
    else if(substr($value, -1) == ';' )
    {
        $value = $value.$append;
    }
    else if(strlen(preg_replace('/[^a-zA-Z]/', '', $value)) < 2)
    {

    }
    else if(substr( $value, 0, 4 ) === "else")
    {
        $value = $value.$append;
    }
    else
    {
        $value = $append.$value ;
    }

}


}
file_put_contents("example.php", implode("\n", $lines));

header("example.php");

Then the file (example.php) will change as following:

<?php  ;      
 $total = NULL;    $total = $total . __LINE__ . " - " ; 
  $total = $total . __LINE__ . " - " ; $a = "Hello World! ";  
  $total = $total . __LINE__ . " - " ; $b = "Welcome ";  
  $total = $total . __LINE__ . " - " ; if(isset($a)) {
  $total = $total . __LINE__ . " - " ;    echo true;   }
  $total = $total . __LINE__ . " - " ; if(isset($b)) {
  $total = $total . __LINE__ . " - " ;    echo true;   }
else {        
  $total = $total . __LINE__ . " - " ; 
  $total = $total . __LINE__ . " - " ;    echo false; 
}
  echo $total; ?>

Which will print the path that executed at this run:

(Result)

2 - 3 - 4 - 5 - 6 - 7 - 8 -

Can anyone help me to find more robust way to get the path of PHP source code based on most of PHP syntax senario. or if any tool can do it and get the line numbers of PHP source code that executed at that time.

Thanks in advance

来源：https://stackoverflow.com/questions/59128514/how-to-print-a-variable-in-single-quotations-in-php

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