问题
The exact situation is next:
I have defined in system API structs CGPoint and CGSize, and I want to be able to write my_point = my_size.
I can't modify CGPoint struct, only can write external operator. I can write binary operators (+, -, ...) but operator= must by declared inside struct. So is there any other solution?
回答1:
To make the expression a = b; compile you need to either have an operator= in the type of a that takes an element of the type of b, or a type implicitly convertible from b.
The first case is ruled out, since operator= must be a member of the class, and since you cannot modify GLPoint then you cannot add GLPoint& GLPoint::operator=( GLSize ).
The second case suffers the same type of problems. An implicit conversion from GLSize to GLPoint can be implemented as an implicit constructor in GLPoint (ruled out), or as a member operator GLPoint() in GLSize, which requires modification of GLSize. Conversions cannot be added as free functions either.
The alternatives are using non-operator syntax, as adding a free function assign (or copy): GLPoint& assign( GLPoint&, GLSize const & ).
The next question is why would you want to do so. If the designers of GLPoint and GLSize did not consider that a size should be assignable to a point, then why do you feel that they should be assignable? In general it is a good idea to keep types separate, as that will enable the compiler to detect mistakes you might make in your code.
If you allow implicit conversions from GLSize to GLPoint, you might by mistake type something like: distance( point1, size2 ) where you meant distance( point1, point2 ), and because there is a conversion, the compiler will gladly convert and apply. Then you will see strange results, and you will spend quite a few nice debugging hours trying to determine where the logic is wrong.
Unless the domain has a very clear definition of what each operator means in that context, I would avoid operator overloading at all costs. Will everyone reading your code immediately understand what GLPoint(1,2) + GLSize(5) represents without any doubt or ambiguity? If that is not the case, if people will be surprised or even doubt, then avoid operator overloading and use named functions: move_up( GLPoint&, GLSize ) (or whatever point+size means to you)
回答2:
When you assign a CGSize to a CGPoint - what happens? Distil that into some operator and there you have it - for example
CGPoint& operator|=(CGPoint& cPoint, CGSize const& cSize)
{
// now set attributes of cPoint that you can extract from cSize
return cPoint;
}
What's so difficult about this? Here is an example: http://www.ideone.com/FZN20
回答3:
If you can derive from or wrap CGPoint and use the new class instead throughout your code, then you can provide whatever operators you like. The new class can have a conversion operator to CGPoint facilitating interaction with existing functions.
回答4:
Other answers seams to miss the obvious solution : add a function to convert CGPoint into CGSize. Off course, that is not exactly what you want (size = point), but since you can not modify either of two classes, this is the only way :
CGSize ToSize( const CGPoint &pt )
{
CGSize res = ...
// do the conversion
return res;
}
来源：https://stackoverflow.com/questions/6120841/is-it-possible-to-write-auto-cast-operator-outside-a-struct