问题
If I have for example this simple TCP server:
from twisted.internet import reactor
from twisted.web.resource import Resource
from twisted.web.server import Site
from resources import SomeResource
logging.info("Starting server...")
root = Resource()
root.putChild("test", SomeResource())
reactor.listenTCP(8080, Site(root))
reactor.run()
With SomeResource which has the render_GET and render_POST methods for example. Then I know I can just send a POST/GET to hostname:8080/test
But now I want to make it more complicated, I would like to do something like hostname:8080/test/status
Could that be defined inside SomeResource() as a method? or do I have to define a new resource for every different url?
回答1:
If you want everything that goes to /test/.... to get to the render (render_GET/render_POST) method of SomeResource, just define it as a leaf:
class SomeResource(Resource):
isLeaf = True
If you want to look at the part after "test/", request.postpath will include that.
来源：https://stackoverflow.com/questions/37676872/twisted-url-action-routing