问题
I have a table that stores some student work info. I need to select the hours based on the studentID and the quarter ID. Here is what I have:
SELECT
(SELECT hours FROM clinicalStudents WHERE quarterID='201101' and studentID='$studentID') as q1,
(SELECT hours FROM clinicalStudents WHERE quarterID='201102' and studentID='$studentID') as q2,
(SELECT hours FROM clinicalStudents WHERE quarterID='201103' and studentID='$studentID') as q3,
(SELECT hours FROM clinicalStudents WHERE quarterID='201104' and studentID='$studentID') as q4
It's only giving me some numbers but not all of them. I ran this (minus the WHERE clause) in my server manager and received an error:
"Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <=, >, >= or when the subquery is used as an expression"
Any assistance would be great. Thanks!
EDIT:
The $studentID is generated in a while loop so I'm using the hours on that student before I move to the next one. I'm getting all the hours for one student in each quarter, adding them (this has to be done outside of the sql), storing results in a variable then moving to the next student. This works perfect when I get 1 quarter but i'm having an issue getting all the quarters.
EDIT Round 2: Did it in a rather lazy way I suppose:
I just selected all the hours and quarterID's for a specific student. Then ran a while(odbc_fetch_row()). If it was a 201101 I added it to the $q1 pile, 201102 added to the $q2 pile, and so on. Processing is a little slower but not a big issue with what I'm doing.
回答1:
trying use a SELECT TOP 1
or a LIMIT 1
in the query, depending which sql you are running.
EDIT Also, why are you trying to accomplish? This seems clunky and, depending your intended purpose, there is probably a better way available.
回答2:
I'm not sure what's your goal...
Maybe what you really want is:
select quarterID, sum(hours)
from clinicalStudents
where studentID='$studentID'
group by 1
回答3:
SELECT
hours, SUBSTR(quarterId, 4, 2)
FROM
clinicalStudents
WHERE
quarterID IN ('201101', '201102', '201103', '201104') and studentID='$studentID'
Depending on what database you are using, you will have to change the function SUBSTR
回答4:
EDIT on loop.
Don't use a loop to do a SUM operation. Instead use the SUM aggregation operation
The allows you to project each quarter to each column.
SELECT
cs.studentid , q1.hours Q1, q2.hours Q2, q3.hours Q3, q4.hours Q4
FROM
clinicalStudents cs
(SELECT SUM(hours) hours , studentID
FROM clinicalStudents
WHERE quarterID='201101' and studentID='$studentID'
GROUP BY studentID ) q1
LEFT join on cs.studentID = q1.clinicalStudents
(SELECT SUM(hours) hours , studentID
FROM clinicalStudents WHERE quarterID='201102' and studentID='$studentID'
GROUP BY studentID ) q2
LEFT join on cs.studentID = q2.clinicalStudents
(SELECT SUM(hours) hours , studentID
FROM clinicalStudents
WHERE quarterID='201103' and studentID='$studentID'
GROUP BY studentID ) q3
LEFT join on cs.studentID = q3.clinicalStudents
(SELECT SUM(hours) hours , studentID
FROM clinicalStudents
WHERE quarterID='201104' and studentID='$studentID' GROUP BY studentID ) q4
LEFT join on cs.studentID = q4.clinicalStudents
WHERE cs.studentID='$studentID'
回答5:
Try this.
select studentID
,sum(case when quarterID = '201101' then hours end) as q1
,sum(case when quarterID = '201102' then hours end) as q2
,sum(case when quarterID = '201103' then hours end) as q3
,sum(case when quarterID = '201104' then hours end) as q4
from clinicalStudents
where quarterID in('201101', '201102', '201103', '201104')
group by studentID;
来源:https://stackoverflow.com/questions/4391903/how-can-i-make-multiple-select-statements-on-the-same-table