slug candidates rails 4

问题

I have Job model and Location model in my rails application. I am using postgresql as a database.so i have location_ids as an array field in my Job model for holding locations. I am using FeriendlyId in my application to make my url friendly. when i go to my job show page i am getting this friendly url

http://localhost:3000/jobs/seo-trainee

but now i also want to include the locations the job has in my url , something like this

http://localhost:3000/jobs/seo-trainee-mumbai-tokyo

i know we can use slug_candidates for this purpose. but i dont know how can i achieve this exactly

currently i have this in my Job model

 extend FriendlyId
 friendly_id :slug_candidates, use: [:slugged, :finders]

 def slug_candidates
  [
    :title,
    [:title, :id]
  ]
 end

回答1:

You need to define a custom method to generate your slug definition, and then tell FriendlyId to use that method.

The documentation gives this example:

class Person < ActiveRecord::Base
  friendly_id :name_and_location
  def name_and_location
    "#{name} from #{location}"
  end
end

bob = Person.create! :name => "Bob Smith", :location => "New York City"
bob.friendly_id #=> "bob-smith-from-new-york-city"

So in your case, you would use something like this:

class SomeClass
  friendly_id :job_name_and_location

  def job_name_and_location
    "#{name} #{locations.map(&:name).join(' ')}"
  end
end

I've made a few assumptions:

Your job model has a name attribute (seo training)
Your job model has_many locations, each of which have a name attribute

We then create a method which defines the non-friendly string which FriendlyId will use to create a slug from. In this case it'll come up with something like SEO Training Mumbai Tokyo and use that to create your seo-training-mumbai-tokyo slug.

回答2:

You can use something like the following:

extend FriendlyId
 friendly_id :slug_candidates, use: [:slugged, :finders]

 def slug_candidates
   locs = Location.where("id IN(?)", self.location_ids).collect{|l| l.name}.join("-") // here, we find the locations for the current job, then joins the each locations name with a '-' sign
   return self.title+"-"+locs // here, returns the job title with the location names
 end

So, if your current Job holds location_ids = [1,2,3] then from Location table we find the locations with id = 1,2,3. Then join their names.

来源：https://stackoverflow.com/questions/29764036/slug-candidates-rails-4

标签

ruby-on-rails

friendly-id