Are char * argv[] arguments in main null terminated?

问题

So I'm wondering if command line parameters are always null terminated? Google seems to say yes, and compiling on GCC indicates this is the case, but can I guarantee this to always be true?

int main(int argc, char** argv)
{
    char *p;

    for(int cnt=1; cnt < argc; ++cnt)
    {
        p = argv[cnt];
        printf("%d = [%s]\n", cnt, p);
    }
    return 0;
}

$ MyProgram -arg1 -arg2 -arg3
1 = -arg1
2 = -arg2
3 = -arg3

回答1:

Yes. The non-null pointers in the argv array point to C strings, which are by definition null terminated.

The C Language Standard simply states that the array members "shall contain pointers to strings" (C99 §5.1.2.2.1/2). A string is "a contiguous sequence of characters terminated by and including the first null character" (C99 §7.1.1/1), that is, they are null terminated by definition.

Further, the array element at argv[argc] is a null pointer, so the array itself is also, in a sense, "null terminated."

回答2:

Yes, it is always true that the arguments are null terminated strings.

来源：https://stackoverflow.com/questions/11020172/are-char-argv-arguments-in-main-null-terminated