问题
I have a table like this :
CustName Country RecordedTime
---------------------------------------------
Alex Australia 2018-Jun-01 08:00 AM
Alex China 2018-Jun-01 10:00 AM
Alex Japan 2018-Jun-01 11:00 AM
John Australia 2018-Jun-01 08:00 AM
John China 2018-Jun-02 08:00 AM
Bob Australia 2018-Jun-02 09:00 AM
Bob Brazil 2018-Jun-03 09:50 AM
If the record is brand new in the system then it should show 'ADD' & 'NEW' in Audit and history fields (two additional fields in result set) for the given date.
If the record got edited twice that day then it should show two entries with 'ADD' & 'CHANGE ' in Audit fields and 'BEFORE' & 'CURRENT' in History state fields respectively for the given date.
For example this is how my result should appear;
When I pass input date as 2018-Jun-01 then the output should be as below:
CustName Country RecordedTime Audit History
----------------------------------------------------------------
Alex Australia 2018-Jun-01 08:00 AM ADD NEW
Alex China 2018-Jun-01 10:00 AM CHANGE BEFORE
Alex Japan 2018-Jun-01 11:00 AM CHANGE CURRENT
John Australia 2018-Jun-01 08:00 AM ADD NEW
When I pass the input date as 2018-Jun-02 then the output should be as below:
CustName Country RecordedTime Audit History
-----------------------------------------------------------------
John China 2018-Jun-02 08:00 AM CHANGE CURRENT
Bob Australia 2018-Jun-02 09:00 AM ADD NEW
When I pass input date as 2018-Jun-02 then the output should be as below:
CustName Country RecordedTime Audit History
----------------------------------------------------------------
Bob Brazil 2018-Jun-03 09:50 AM CHANGE CURRENT
I tried many ways but still I'm missing some scenarios to achieve this. Can someone please shed some light on this?
回答1:
One way to do it is via a cte like below where we have row_number() function to track the sequence both ways.
See live demo
; with cte as
(
select *, rn= row_number() over(partition by CustName order by RecordedTime),
rn2=row_number() over(partition by CustName order by RecordedTime desc)
from records
)
, cte2 as
(
select *, audit='New', History='Change' from cte where rn=1
union
select *, audit='Change', History='Current' from cte where rn2=1 and rn<>1
union
select *, audit='Change', History='before' from cte where rn>1 and rn2<>1
)
select
CustName,
Country,
RecordedTime,
audit,
History
from cte2
order by CustName,RecordedTime
回答2:
I would simply use case
expressions.
select t.*,
(case when seqnum = 1 then 'ADD' else 'CHANGE' end) as audit,
(case when seqnum = 1 then 'NEW'
when seqnum_day = 1 then 'CURRENT'
else 'BEFORE'
end) as history
from (select t.*,
row_number() over (partition by custname order by recordedtime) as seqnum,
row_number() over (partition by custname, cast(recordedtime as date) order by recordedtime desc) as seqnum_day
from t
) t;
sqlfiddle:http://sqlfiddle.com/#!18/43c08/27
回答3:
You can try.
CASE WHEN
and RANK
with Windows function
;WITH CTE (CustName,Country,RecordedTime,rn) AS(
SELECT *,RANK() OVER(PARTITION BY CustName ORDER BY RecordedTime) rn
FROM T
)
SELECT t.*,
(CASE WHEN rn = 1 then 'ADD' ELSE 'CHANGE' END) 'Audit',
(CASE
WHEN rn = 1 then 'NEW'
WHEN t2.mRn = rn then 'CURRENT'
ELSE 'BEFORE' END) 'History'
FROM CTE t LEFT JOIN (
SELECT MAX(rn) mRn,CustName FROM CTE GROUP BY CustName
) t2 on t2.mRn = t.rn and t2.CustName = t.CustName
WHERE CONVERT(char(10), RecordedTime,126) = '2018-06-02'
sqlfiddle:http://sqlfiddle.com/#!18/43c08/26
来源:https://stackoverflow.com/questions/51030093/how-to-retrieve-data-from-sql-server-as-required-below