Getting input with IUP in Lua

扶醉桌前 提交于 2019-12-11 04:44:37

问题


I've been trying to get input with IUP to make a small pong game. I wanted to try some input, and tried some of the code that comes with the IUPGL examples, but the input doesn't seem to be working at all. Here's the code as it stands so far:

require "iuplua"
require "iupluagl"
require "luagl"

paddle = {x = -0.9, y = 0.2}

function drawPaddle(x, y)
    gl.Begin(gl.QUADS)
    gl.Color(0.0, 0.5, 0.0)

    gl.Vertex(x, y)
    gl.Vertex(x + 0.1, y)
    gl.Vertex(x + 0.1, y - 0.4)
    gl.Vertex(x, y - 0.4)
end

canvas = iup.glcanvas{buffer = "DOUBLE", rastersize = "300x300"}

function canvas:action(x, y)
    iup.GLMakeCurrent(self)
    gl.ClearColor(0.0, 0.0, 0.0, 0.0)
    gl.Clear(gl.COLOR_BUFFER_BIT)
    gl.Clear(gl.DEPTH_BUFFER_BIT)

    gl.MatrixMode(gl.PROJECTION)
    gl.Viewport(0, 0, 300, 300)
    gl.LoadIdentity()

    drawPaddle(paddle.x, paddle.y)

    gl.End()
    iup.GLSwapBuffers(self)
end

window = iup.dialog{canvas, title = "Soon to be Pong"}

function canvas:k_any(c)
    if c == iup.K_q then
        return iup.CLOSE
    elseif c == iup.K_w then
        paddle.y = paddle.y + 0.02
        return iup.CONTINUE
    else
        return iup.DEFAULT
    end
end

window:show()

iup.MainLoop()

It's my understanding that canvas:k_any() gets called when a key is pressed, but it's not responding, even to the quit command. Any ideas?


回答1:


Here is at least part of the problem for the sample you've quoted. Before the IUP keyname constants are actually defined in your iup table, you need to call a function. The idea is that the memory footprint is lower if you don't need all of the key names, which many applications can do entirely without.

Try adding the following lines sometime shortly after require "iuplua" and before you use the names in any code:

iup.key_open()      -- load key names

This is documented near the top of the topic Keyboard Codes as well as in a variety of places related to the keyboard.

Without the call to iup.key_open(), iup.K_q evaluates to nil (as does any other key name) and thus silently never matches any keycode passed to canvas:k_any().

Edit: I just ran your sample, and indeed calling iup.key_open() causes the q and w keys to be recognized. You have a further glitch you will notice next that just updating the paddle's position doesn't ask for the canvas to redraw. I'll leave that as an exercise as you go forward.

Edit2: Adding the line iup.Update(self) to the function canvas:k_any() just after you modify the state of the paddle appears to do what you want. Doing it that way rather than manually calling the action() method has the advantage of interacting with IUP's message loop handling in the expected way. In the general case, calling iup.UpdateChildren(window) instead might be preferred. That would keep any other IUP controls that are displayed in the dialog updated as well as the canvas, which can be useful if you have controls that don't do all their own updating internally.

Alternatively, you could move the drawing routines into their own function called from both the k_any() and action() methods of the canvas. I'm not sure I'd recommend that in general as it doesn't scale as well when you want to support multiple viewports or related controls.

You might want to rearrange the logic in your k_any() handler so that you are less likely to accidentally forget the call to iup.Update() as you add cases for new keys.



来源:https://stackoverflow.com/questions/821893/getting-input-with-iup-in-lua

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!