问题
The example code for RabbitMQ states
Our code will block while our $channel has callbacks. Whenever we receive a message our $callback function will be passed the received message.
With this code snippet
while(count($channel->callbacks)) {
$channel->wait();
}
This confuses me, because the default timeout for PhpAmqpLib\Channel\AbstractChannel::wait is forever.
public function wait($allowed_methods = null, $non_blocking = false, $timeout = 0)
So if wait blocks forever, how would the code ever reach a second iteration of the while loop?
Would it be safe to say the while loop is only necessary if wait is passed a $timeout > 0?
回答1:
The timeout parameter on the wait call is how long to wait for the next message before giving up. The default value, as you say, is "forever", which means "until a message arrives".
However, once a single message has been received and processed, the wait call exits; it could perhaps be named waitForNextEvent(). You can see that in the source you linked to:
if ($this->should_dispatch_method($allowed_methods, $method_sig)) {
return $this->dispatch($method_sig, $args, $amqpMessage);
}
So to receive more than one message, you need to call wait() more than once. Generally, in a consumer, you want to call it an infinite number of times, so you could just use while(true), but allowing the loop to exit if you unregister all your callbacks gives you a way of gracefully exiting.
回答2:
the code you are showing, would represent the worker or processor of the AMQP messages
Because it will listen for dropped messages from the AMQP server, it will be waiting/listening/looping forever for these messages.
来源：https://stackoverflow.com/questions/42933465/php-amqp-channel-callback-loop