问题
I am trying to parse this string :
'200|50|jo.th@xxx.com|09\23\2016|07:00:00'
into 5 columns and I am getting frustrated.
The delimiter is pipe |
The fields are not fixed so I need to use charindex in order to find the location of the delimiter ?
Please help Thanks
回答1:
Another option is as follows. This can be baked into a TVF or even a Cross Apply
Declare @String varchar(max) = '200|50|jo.th@xxx.com|09\23\2016|07:00:00'
Select Pos1 = xDim.value('/x[1]','varchar(max)')
,Pos2 = xDim.value('/x[2]','varchar(max)')
,Pos3 = xDim.value('/x[3]','varchar(max)')
,Pos4 = xDim.value('/x[4]','varchar(max)')
,Pos5 = xDim.value('/x[5]','varchar(max)')
,Pos6 = xDim.value('/x[6]','varchar(max)')
,Pos7 = xDim.value('/x[7]','varchar(max)')
,Pos8 = xDim.value('/x[8]','varchar(max)')
,Pos9 = xDim.value('/x[9]','varchar(max)')
From (Select Cast('<x>' + Replace(@String,'|','</x><x>')+'</x>' as XML) as xDim) A
Returns
Edit - To Use in a Cross Apply - Easy to expand/contract
Declare @YourTable table (ID int,SomeString varchar(max))
Insert Into @YourTable values
(1,'200|50|jo.th@xxx.com|09\23\2016|07:00:00'),
(2,'400|99|james.th@xxx.com|11\15\2016|09:00:00')
Select A.ID
,B.*
From @YourTable A
Cross Apply (
Select Pos1 = xDim.value('/x[1]','varchar(max)')
,Pos2 = xDim.value('/x[2]','varchar(max)')
,Pos3 = xDim.value('/x[3]','varchar(max)')
,Pos4 = xDim.value('/x[4]','varchar(max)')
,Pos5 = xDim.value('/x[5]','varchar(max)')
,Pos6 = xDim.value('/x[6]','varchar(max)')
,Pos7 = xDim.value('/x[7]','varchar(max)')
,Pos8 = xDim.value('/x[8]','varchar(max)')
,Pos9 = xDim.value('/x[9]','varchar(max)')
From (Select Cast('<x>' + Replace(A.SomeString,'|','</x><x>')+'</x>' as XML) as xDim) A
) B
Returns
回答2:
So first I'd locate the position of each delimiter and then use this to split your string. Something like this;
DECLARE @TextString nvarchar(100); SET @TextString = '200|50|jo.th@xxx.com|09\23\2016|07:00:00'
DECLARE @FirstDelimiter int
DECLARE @SecondDelimiter int
DECLARE @ThirdDelimiter int
DECLARE @FourthDelimiter int
SET @FirstDelimiter = CHARINDEX('|',@TextString)
SET @SecondDelimiter = CHARINDEX('|',@TextString,@FirstDelimiter+1)
SET @ThirdDelimiter = CHARINDEX('|',@TextString,@SecondDelimiter+1)
SET @FourthDelimiter = CHARINDEX('|',@TextString,@ThirdDelimiter+1)
Final Query;
SELECT
@TextString Main_String
,SUBSTRING(@TextString,1,@FirstDelimiter-1) First_String
,SUBSTRING(@TextString,@FirstDelimiter+1,(@SecondDelimiter-@FirstDelimiter)-1) Second_String
,SUBSTRING(@TextString,@SecondDelimiter+1,(@ThirdDelimiter-@SecondDelimiter)-1) Third_String
,SUBSTRING(@TextString,@ThirdDelimiter+1,(@FourthDelimiter-@ThirdDelimiter)-1) Fourth_String
,SUBSTRING(@TextString,@FourthDelimiter+1,LEN(@TextString)-@FourthDelimiter) Fifth_String
Result Set;
Main_String First_String Second_String Third_String Fourth_String Fifth_String
200|50|jo.th@xxx.com|09\23\2016|07:00:00 200 50 jo.th@xxx.com 09\23\2016 07:00:00
回答3:
I use the following to get delimnated values into a set of tables rows (usually for passing in multiple values in a stored procedure parameter which can then be joined on), pivoting can transform it into columns.
(Compatible with SQL Server 2005 and later)
DECLARE @Input varchar(MAX)
DECLARE @Delim char(1)
SET @Input = '200|50|jo.th@xxx.com|09\23\2016|07:00:00'
SET @Delim = '|'
DECLARE @VALUES TABLE (ColNo INT, [Param] varchar(MAX))
DECLARE @ChrInd INT
DECLARE @Piece varchar(MAX)
DECLARE @ColNo INT
SET @ColNo = 1
SELECT @ChrInd = 1
WHILE @ChrInd > 0
BEGIN
SELECT @ChrInd = CHARINDEX(@Delim,@Input)
IF @ChrInd > 0
SELECT @Piece = LEFT(@Input,@ChrInd - 1)
ELSE
SELECT @Piece = @Input
INSERT INTO @VALUES(ColNo, [Param]) VALUES(@ColNo, @Piece)
SELECT @Input = RIGHT(@Input,LEN(@Input) - @ChrInd)
IF LEN(@Input) = 0 BREAK
SET @ColNo = @ColNo + 1
END
--SELECT AS ROWS
SELECT * FROM @VALUES
--SELECT AS COLUMNS
SELECT * FROM
(
SELECT ColNo, [Param] FROM @VALUES
) src
PIVOT(
MAX([Param])
FOR ColNo IN ([1],[2],[3],[4],[5])
) AS pvt
Results
ColNo Param
--------------------------------------------------------------------------
1 200
2 50
3 jo.th@xxx.com
4 09\23\2016
5 07:00:00
1 2 3 4 5
--------- --------- --------------- ----------- ----------
200 50 jo.th@xxx.com 09\23\2016 07:00:00
来源:https://stackoverflow.com/questions/40609102/tsql-parse-string-with-4-delimiters