ZeroMQ FiniteStateMachineException in REQ/REP pattern

六眼飞鱼酱① 提交于 2019-12-11 00:19:29

问题


I have two simple components which are supposed to communicate with each other using the REQ/REP ZeroMQ pattern. The Server (REP Socket) is implemented in Python using pyzmq:

import zmq

def launch_server():
    print "Launching server"
    with zmq.Context.instance() as ctx:
        socket = ctx.socket(zmq.REP)
        socket.bind('tcp://127.0.0.1:5555')

        while True:
            msg = socket.recv()
            print "EOM\n\n"

The Client (REQ socket) written in C# using the NetMQ library:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using NetMQ;


namespace PyNetMQTest
{
    class Program
    {

        static void Main(string[] args)
        {
            string msg;
            NetMQ.Sockets.RequestSocket socket = new NetMQ.Sockets.RequestSocket();
            socket.Connect("tcp://127.0.0.1:5555");
            for(int i=0; i<5; i++)
                socket.SendFrame("test_"+i);
        }
    }
}

The Python Server implementation has been tested and works fine by talking to a REQ socket implemented using Python. But the C# REQ socket throws the following error within the first iteration of the loop and no messages reach the Server whatsoever:

An unhandled exception of type 'NetMQ.FiniteStateMachineException' occurred in NetMQ.dll Additional information: Req.XSend - cannot send another request

Stacktrace:

at NetMQ.Core.Patterns.Req.XSend(Msg& msg)
   at NetMQ.Core.SocketBase.TrySend(Msg& msg, TimeSpan timeout, Boolean more)
   at NetMQ.NetMQSocket.TrySend(Msg& msg, TimeSpan timeout, Boolean more)
   at NetMQ.OutgoingSocketExtensions.Send(IOutgoingSocket socket, Msg& msg, Boolean more)
   at NetMQ.OutgoingSocketExtensions.SendFrame(IOutgoingSocket socket, String message, Boolean more)
   at PyNetMQTest.Program.Main(String[] args) in d:\users\emes\documents\visual studio 2015\Projects\PyNetMQ Test\PyNetMQTest\Program.cs:line 20
   at System.AppDomain._nExecuteAssembly(RuntimeAssembly assembly, String[] args)
   at System.AppDomain.ExecuteAssembly(String assemblyFile, Evidence assemblySecurity, String[] args)
   at Microsoft.VisualStudio.HostingProcess.HostProc.RunUsersAssembly()
   at System.Threading.ThreadHelper.ThreadStart_Context(Object state)
   at System.Threading.ExecutionContext.RunInternal(ExecutionContext executionContext, ContextCallback callback, Object state, Boolean preserveSyncCtx)
   at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state, Boolean preserveSyncCtx)
   at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state)
   at System.Threading.ThreadHelper.ThreadStart()

These are the first my first steps with ZMQ and the C# code is taken from the library documentation. What makes the code throw this error?

I am using:

  • pyzmq 14.7
  • NetMQ 3.3.3.4
  • .NET 4.6

====================== SOLUTION ======================

As explained by @somdoron in his answer, th roor casue was that both sockets need to go the full cycle of send/receive before beeing able to be reused. As a matter of fact the REP socket implemented in python did not ever change it's state either so the error was in both, the python AND the C# code. Here is the fixed code:

REP Socket

import zmq

def launch_server():
    print "Launching server"
    with zmq.Context.instance() as ctx:
        socket = ctx.socket(zmq.REP)
        socket.bind('tcp://127.0.0.1:5555')

        while True:
            msg = socket.recv()
            socket.send("reply to "+msg)
            print "EOM\n\n"

REQ Socket

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using NetMQ;


namespace PyNetMQTest
{
    class Program
    {

        static void Main(string[] args)
        {

            NetMQ.Sockets.RequestSocket socket = new NetMQ.Sockets.RequestSocket();
            socket.Connect("tcp://127.0.0.1:5555");

            string msg, reply;

            while (true)
            {
                Console.WriteLine("Type message: ");
                msg = Console.ReadLine();
                Console.WriteLine("Sending : " + msg);
                socket.SendFrame(msg);
                reply = socket.ReceiveFrameString();
                Console.WriteLine("Received: " + reply + Environment.NewLine);
            }
        }
    }
}

回答1:


Request and Response sockets are state machines, with Request you must first Send and then call Receive, you cannot call 5 consecutive Send.

With Response its the opposite, you must call Receive first.

If one side is only sending and the other only receiving you can use Push-Pull pattern instead of Req-Rep. You can also use Dealer-Router if needed both ways communication. Anyway it seems the usage of Req-Rep is incorrect.



来源:https://stackoverflow.com/questions/39860614/zeromq-finitestatemachineexception-in-req-rep-pattern

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