问题
I am trying to use Z3 to produce a model for a set of SAT assertions describing a partial order theory. I tried the subtype example in Z3 guide but it seems I cannot get a concrete model. Is there a way that Z3 can produce a model that describes the orders among elements and satisfies all assertions I made?
For example, following are the constraints for "subtype". Is it possible that Z3 may produce a model like "int-type *<* real-type *<* complex-type *<* obj-type *<* root-type" and "string-type *<* obj-type *<* root-type" (if I use "*<*" to denote subtype relation)?
(set-option :produce-models true)
(declare-sort Type)
(declare-fun subtype (Type Type) Bool)
(assert (forall ((x Type)) (subtype x x)))
(assert (forall ((x Type) (y Type))
(=> (and (subtype x y) (subtype y x))
(= x y))))
(assert (forall ((x Type) (y Type) (z Type))
(=> (and (subtype x y) (subtype y z))
(subtype x z))))
(assert (forall ((x Type) (y Type) (z Type))
(=> (and (subtype x y) (subtype x z))
(or (subtype y z) (subtype z y)))))
(declare-const obj-type Type)
(declare-const int-type Type)
(declare-const real-type Type)
(declare-const complex-type Type)
(declare-const string-type Type)
(assert (forall ((x Type)) (subtype x obj-type)))
(assert (subtype int-type real-type))
(assert (subtype real-type complex-type))
(assert (not (subtype string-type real-type)))
(declare-const root-type Type)
(assert (subtype obj-type root-type))
(check-sat)
(get-model)
Currently, I got
sat
(model
;; universe for Type:
;; Type!val!0 Type!val!3 Type!val!2 Type!val!4 Type!val!1
;; -----------
;; definitions for universe elements:
(declare-fun Type!val!0 () Type)
(declare-fun Type!val!3 () Type)
(declare-fun Type!val!2 () Type)
(declare-fun Type!val!4 () Type)
(declare-fun Type!val!1 () Type)
;; cardinality constraint:
(forall ((x Type))
(or (= x Type!val!0)
(= x Type!val!3)
(= x Type!val!2)
(= x Type!val!4)
(= x Type!val!1)))
;; -----------
(define-fun complex-type () Type
Type!val!2)
(define-fun real-type () Type
Type!val!1)
(define-fun obj-type () Type
Type!val!4)
(define-fun root-type () Type
Type!val!4)
(define-fun string-type () Type
Type!val!3)
(define-fun int-type () Type
Type!val!0)
(define-fun subtype!73 ((x!1 Type) (x!2 Type)) Bool
(ite (and (= x!1 Type!val!3) (= x!2 Type!val!1)) false
(ite (and (= x!1 Type!val!2) (= x!2 Type!val!3)) false
(ite (and (= x!1 Type!val!4) (= x!2 Type!val!1)) false
(ite (and (= x!1 Type!val!4) (= x!2 Type!val!3)) false
(ite (and (= x!1 Type!val!2) (= x!2 Type!val!1)) false
(ite (and (= x!1 Type!val!1) (= x!2 Type!val!3)) false
(ite (and (= x!1 Type!val!4) (= x!2 Type!val!0)) false
(ite (and (= x!1 Type!val!4) (= x!2 Type!val!2)) false
(ite (and (= x!1 Type!val!0) (= x!2 Type!val!3)) false
(ite (and (= x!1 Type!val!2) (= x!2 Type!val!0)) false
(ite (and (= x!1 Type!val!1) (= x!2 Type!val!0)) false
(ite (and (= x!1 Type!val!3) (= x!2 Type!val!0)) false
true)))))))))))))
(define-fun k!72 ((x!1 Type)) Type
(ite (= x!1 Type!val!1) Type!val!1
(ite (= x!1 Type!val!4) Type!val!4
(ite (= x!1 Type!val!3) Type!val!3
(ite (= x!1 Type!val!0) Type!val!0
Type!val!2)))))
(define-fun subtype ((x!1 Type) (x!2 Type)) Bool
(subtype!73 (k!72 x!1) (k!72 x!2)))
)
Thank you in advance for any help you could give.
回答1:
I think that your line
(assert (forall ((x Type)) (subtype x obj-type)))
is wrong.
The correct is
(assert (forall ((x Type)) (subtype x root-type)))
The possible correct model is obtained here
来源:https://stackoverflow.com/questions/22334501/how-to-produce-the-model-for-partial-orders