How to read Maven properties from JUnit test?

问题

I'm using Maven 3.0.3 with JUnit 4.8.1. In my JUnit test, how do I read the project.artifactId defined in my Maven pom.xml file? In my pom, I have

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>

<groupId>com.myco.pplus2</groupId>
<artifactId>pplus2</artifactId>

But this isn't working within my JUnit test to gete the artifact id ...

@Before
public void setUp() { 
    ...        
    System.out.println( "artifactId:" + System.getProperty("project.build.sourceEncoding") ); 
}   // setUp

The above outputs "artifactId:null". Anyway, appreciate any help, - Dave

回答1:

Look at the systemPropertyVariables (and friends) for surefire. It does what you want. AFAIK there is no way to just pass all the maven properties without listing them.

回答2:

Maven project properties aren't automatically added to Java System properties. To achieve that there are quite a few options. For this specific need you could define a System property for maven-surefire-plugin (the one running tests) and then use the System.getProperty method.

<plugin>
    <groupId>org.apache.maven.plugins</groupId>
    <artifactId>maven-surefire-plugin</artifactId>
    <version>2.10</version>
    <configuration>
        <systemProperties>
            <property>
                <name>projectArtifactId</name>
                <value>${project.artifactId}</value>
            </property>
        </systemProperties>
    </configuration>
</plugin>

Other way to achieve getting Maven properties to JUnit tests would probably be resources filtering for test source files.

PS. Reading Maven configurations at runtime, even in tests is pretty dirty IMHO. :)

回答3:

Sometimes, Eclipse is configured to use the Java Builder for Project->Automatically Build (Right Click->Project->Properties->Builders)

If such is the case, sometimes the resource filtering doesn't work. You have several options:

Provide the property in the pom.xml file as above.
Provide a properties file and perform Maven resource filtering
Use the Maven Invoker

2 and 3 are described in http://scottizu.wordpress.com/2013/10/16/reading-the-project-version-from-the-maven-pom-file/

来源：https://stackoverflow.com/questions/7903621/how-to-read-maven-properties-from-junit-test

标签

maven

junit

system-properties