问题
I've read about subquery in Criteria, but I am still unable to grasp it properly. Here I am taking one example and if somebody can help me write that using subquery it will be great.
Lets say we have table
Employee{EmployeeId.(int),Name(string),Post(string),No_Of_years_working(int)}
Now I want all the employees who are Managers and working for less than 10 years. I know that we can get the result without using subqueries but I want to use subquery just to understand how it works in criteria.
So, how I can write Criteria using subquery to get those employees.
回答1:
Well - the code should be something like this:
DetachedCriteria dc = DetachedCriteria.For<Employee>()
.Add (Subqueries.PropertyIn("EmployeeId",
DetachedCriteria.For<Employee>()
.SetProjection(Projections.Property("EmployeeId"))
.Add(Restrictions.Lt("No_Of_years_working", 10))
.Add(Restrictions.Eq("Post", "Manager"))
);
Hope this helps.
回答2:
I was trying to perform something similar to Bipul's task, when I found this question, so I mainly got bernhardrusch's answer idea, but I've realized that without adding the Projections.projectionList the subquery do not work. So I've decided to drop a few lines of code with the final version:
Session session; //You get the session according with your app logic
//Let's define first the subquery
DetachedCriteria sub = DetachedCriteria.forClass(Employee.class);
sub.add( Restrictions.lt("No_Of_years_working", 10) );
sub.add( Restrictions.eq("Post", "Manager") );
sub.setProjection(
Projections.projectionList().add( Projections.property("EmployeeId")
)
);
//Now the main query
Criteria criteria = session.createCriteria(Employee.class);
criteria.add( Property.forName("EmployeeId").in(sub) );
来源:https://stackoverflow.com/questions/2779162/write-subquery-in-criteria-of-nhibernate