For example, i have java class JRXlsExporter, if i instantiated that java from java my code is :
JRXlsExporter myObject= new JRXlsExporter();
and from PHP become:
$myObject = new Java("net.sf.jasperreports.engine.export.JRXlsExporter");
It works, but if i have java class with parameter, for example :
JRXlsExporter myObject= new JRXlsExporter(param1,param2);
How to instantiate/call that java class from PHP ?
Here is an example of how java.util.Date
object is instantiated, with some constructor arguments:
$date = new Java("java.util.Date", 70, 9, 4);
Further, it says:
The new Java("java.util.Date", 70, 9, 4) call creates a new instance of the java.util.Date class using the java.util.Date(int year, int month, int day) constructor.
So, you could maybe try this:
$myObject = new Java("net.sf.jasperreports.engine.export.JRXlsExporter", param1, param2);
来源:https://stackoverflow.com/questions/13247418/how-to-instantiate-call-java-class-with-parameter-from-php