问题
I'm running the following RUN command in my Dockerfile, expecting a "logs" directory to be created under each of the listed subdirectories:
RUN mkdir -p /opt/seagull/{diameter-env,h248-env,http-env,msrp-env,octcap-env,radius-env,sip-env,synchro-env,xcap-env}/logs
But when I check the image, I see a directory literally called "{diameter-env,h248-env,http-env,msrp-env,octcap-env,radius-env,sip-env,synchro-env,xcap-env}" created under /opt/seagull, instead of brace expansion taking place.
What could I be doing wrong?
回答1:
You're not using brace expansion, because you're not using Bash. If you look at the documentation for the RUN command:
RUN (shell form, the command is run in a shell, which by default is /bin/sh -c on Linux or cmd /S /C on Windows)
And also:
Note: To use a different shell, other than ‘/bin/sh’, use the exec form passing in the desired shell. For example, RUN ["/bin/bash", "-c", "echo hello"]
So, just change the command to use the exec form and explicitly use a Bash shell:
RUN [ "/bin/bash", "-c", "mkdir -p /opt/seagull/{diameter-env,h248-env,http-env,msrp-env,octcap-env,radius-env,sip-env,synchro-env,xcap-env}/logs" ]
来源：https://stackoverflow.com/questions/40164660/bash-brace-expansion-not-working-on-dockerfile-run-command