问题
I have a ui slider element that I am using to let people rate a product, the purpose is to have this slider along with a button to insert the value into a MySQL table (sort of voting)
my slider looks like
$("#slider-range-max4").slider({
range: "max",
min: 1,
max: 10,
value: 0,
slide: function (event, ui) {
$("#slider-range-max-amount4").text(ui.value);
}
});
$("#slider-range-max-amount1").text($("#slider-range-max1").slider("value"));
How can I use a button to send the value selected by the user to mysql, do I have to embed the code into a form ?
Thanks
回答1:
use ajax like bellow and send the value to php
$(function() {
$( "#slider-range-max" ).slider({
range: "max",
min: 1,
max: 10,
value: 2,
slide: function( event, ui ) {
$( "#amount" ).val( ui.value );
}
});
$( "#amount" ).val( $( "#slider-range-max" ).slider( "value" ) );
$.ajax({
type:"POST",
url:"your.php",
data:"vote="+$( "#slider-range-max" ).slider( "value" ),
success:function(response){
alert(voted);
}
})
});
In PHP
<?php
$vote="";
if(isset($_POST['vote'])){$vote=$_POST['vote']}
//now do your job with MySql here
?>
来源:https://stackoverflow.com/questions/17096883/sending-jquery-ui-slider-values-to-database