Passing array argument to a function

问题

On calling the function

int sum_array(int array[], int arr_length)
{ 
   int sum = 0;  
   while(--arr_length >= 0)
      sum += array[arr_length];
   return sum;
}

in main function

 int main()
{
    int b[10];
    ...
    total = sum_array(b,10);
    ...
}

why passing the argument b , not b[] as sum_array(b[],10)?
NOTE: I have no knowledge of pointers.

回答1:

In C, arrays are passed as a pointer to the first element. The type of b is array.

When passing b, you're actually passing a pointer to the first element of the array.

回答2:

• why passing the parameter b and not b[] as sum_array(b[],10)

Short answer: Because b[] is invalid syntax.

Here

int b[10];

variable b is declared. int [10] is type of variable.

Since functions accept identifiers as parameters, not types, you should pass identifier to function. Identifier is b.

• NOTE: I have no knowledge of pointers.

It has nothing to do with pointers.

回答3:

The function is expecting a pointer to an int array, so you need to pass a pointer to the start of the array. b[10] points to the eleventh (!) index of a ten element array.

来源：https://stackoverflow.com/questions/17353055/passing-array-argument-to-a-function