问题
Background
- Framework: Codeignighter/PyroCMS
I have a DB that stores a list of products, I have a duplicate function
in my application that first looks for the common product name so it can add a 'suffix
' value to the duplicated product.
Code in my Products model class
$product = $this->get($id);
$count = $this->db->like('name', $product->name)->get('products')->num_rows();
$new_product->name = $product->name . ' - ' . $count;
On the second line the application fails only when the $product->name
contains quotes.
I was with the understanding that Codeignighter escaped all strings so I dont know why I get this error.
So I tried to use MySQL escape string function but that didn't help either.
The Error Message
A Database Error Occurred
Error Number: 1064
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 's Book%'' at line 3
SELECT * FROM `products` WHERE `name` LIKE '%Harry\\'s Book%'
var_dump
Below is the output of doing a var_dump
on product->name
before and after the line in question;
string 'Harry's Book' (length=12)
A Database Error Occurred
Error Number: 1064
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 's Book%'' at line 3
SELECT * FROM `products` WHERE `name` LIKE '%Harry\\'s Book%'
回答1:
Let's do some testing about this.
Here is what you are doing
$count = $this->db->like('name', $product->name)->get('products')->num_rows();
And i suspect $product->name
contains this.
Harry's Book
As we know this is coming from the database table as you are using. Where you are using the upper query mentioned it is wrapping it with single quotes and producing this result.
SELECT * FROM `products` WHERE `name` LIKE '%Harry\\'s Book%'
As you see it is escaping apostrophy to tell it is not end of string Therefore escaping it with two slashes.One for apostrophy and one for being in single quote.
What you have to do is Before assigning the parameter to query wrap it with double quotes.
$product_name = "$product->name";
And now pass it to query.
$count = $this->db->like('name', $product_name)->get('products')->num_rows();
The output will be this
SELECT * FROM `products` WHERE `name` LIKE '%Harry\'s Book%'
You see the differece here. It contains single slash now and the record will be found.
回答2:
Other answers didn't work for me, this does though:
$count = $this->db->query("SELECT * FROM `default_firesale_products` WHERE `title` LIKE '".addslashes($product['title'])."'")->num_rows();
Whenever CI Active Record mangles your queries you can always just put a raw query in instead and have full control.
回答3:
Try this, using stripslashes()
around $product->name
:
$count = $this->db->like('name', stripslashes($product->name))->get('products')->num_rows();
CI automatically escapes characters with active records but I bet that it's already escaped if you entered it previously via active record in CI. So now it is doing a double escape.
Update: You may also want to try adding the following before you query:
$this->db->_protect_identifiers = FALSE;
Last try: try querying this way since it seems like the like
active record is causing the error:
$like = $product->name;
$this->db->query("SELECT * FROM `products` WHERE `name` LIKE '%$like%'");
来源:https://stackoverflow.com/questions/18883976/active-record-query-failed-escape-quote-from-query