How to check Url Image is exist or not in php [duplicate]

问题

This question already has answers here:

How can one check to see if a remote file exists using PHP? (21 answers)

Closed 6 years ago.

I am working around fetch image URL from database & show image in php like following

<?php    

$row['blog_url'] = "http://www.nasa.gov/images/content/711375main_grail20121205_4x3_946-710.jpg";

<img src="<?php echo $row['blog_url']; ?>"  height="200" width="200" alt="image"/>

?>

but i want display no_imgae.jpeg if image not getting loaded from specified url as blog_url

if there any way to find out image is exist or not in php

thanks in advance...

回答1:

This function will solve your problem :

function checkRemoteFile($url)
{
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL,$url);
    // don't download content
    curl_setopt($ch, CURLOPT_NOBODY, 1);
    curl_setopt($ch, CURLOPT_FAILONERROR, 1);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    if(curl_exec($ch)!==FALSE)
    {
        return true;
    }
    else
    {
        return false;
    }
}

Just pass the image url in this function and it will return yes if image exists otherwise false

回答2:

$file = "http://www.nasa.gov/images/content/711375main_grail20121205_4x3_946-710.jpg";
$file_headers = @get_headers($file);
if($file_headers[0] == 'HTTP/1.1 404 Not Found') {
    $exists = false;
}
else {
    $exists = true;
}

回答3:

<?
$img = $row['blog_url'];
$headers = get_headers($img);
if(substr($headers[0], 9, 3) == '200') {
?>
<img src="<?php echo $img; ?>"/>
<?
} else {
?>
<img src="noimage.jpg"/>
<?
}
?>

来源：https://stackoverflow.com/questions/15477232/how-to-check-url-image-is-exist-or-not-in-php