问题
I'm receiving a JSON response from a web service, but for various reasons I don't want to have certain properties deserialized in the final response object. For example I have:
public class Foo {
private String bar;
private int baz;
//getters & setters
}
The JSON response I'm getting back has both properties, but upon deserialization I don't want "bar" to be set. The reason for this is that the property they're sending is a long, but ours is a String, so deserializing throws an IllegalArgumentException.
Another option would be to parse the JSON with something like json-simple, remove the properties I want, convert it back to JSON and pass that into the deserializer, but I'd like to avoid that if possible since the JSON is pretty large.
Is there a way to do this with an ObjectFactory perhaps?
回答1:
Yes an ObjectFactory could be used to allow a conversion from Long to String. Simply register the ObjectFactory on your path like:
new JSONDeserializer().use("some.path.to.bar", new EnhancedStringObjectFactory() ).deserialize( json, new SomeObject() );
public class EnhancedStringObjectFactory implements ObjectFactory {
public Object instantiate(ObjectBinder context, Object value, Type targetType, Class targetClass) {
if( value instanceof String ) {
return value;
} else if( value instanceof Number ) {
return ((Number)value).toString();
} else {
throw context.cannotConvertValueToTargetType(value, String.class);
}
}
}
You could even register that as the default ObjectFactory for String and it would handle that case for any String coming into the deserializer:
new JSONDeserializer().use( String.class, new EnhancedStringObjectFactory() ).deserialize( json, new SomeObject() );
来源:https://stackoverflow.com/questions/9589644/flexjson-exclude-properties-upon-deserialization