Failed to open file file.wav as a WAV due to: file does not start with RIFF id

问题

I am getting this error when trying to open a RIFF file (which as I understand it is a type of WAV) in python.

Failed to open file file.wav as a WAV due to: file does not start with RIFF id

When I inspect it with various tools which leads me to believe that it is really a WAV / RIFF file.

$ file file.wav 
file.wav: MBWF/RF64 audio, stereo 96000 Hz


$ file -i file.wav 
file.wav: audio/x-wav; charset=binary




$ mediainfo file.wav 
General
Complete name                            : file.wav
Format                                   : Wave
Format profile                           : RF64
File size                                : 4.10 GiB
Duration                                 : 2h 7mn
Overall bit rate mode                    : Constant
Overall bit rate                         : 4 608 Kbps

Audio
Format                                   : PCM
Format settings, Endianness              : Little
Format settings, Sign                    : Signed
Codec ID                                 : 1
Duration                                 : 2h 7mn
Bit rate mode                            : Constant
Bit rate                                 : 4 608 Kbps
Channel(s)                               : 2 channels
Sampling rate                            : 96.0 KHz
Bit depth                                : 24 bits
Stream size                              : 4.10 GiB (100%)

回答1:

What you have is a 64-bit RIFF. wave does not support 64-bit RIFF files.

回答2:

If your audio is okay, and you are able to read the file with librosa or scipy.io, we can simply read the file, write it back to a temporary wav file and then read it with the wave package again.

Example. Below, we get the RIFF id error.

>>> import wave
>>> wave.open('./SA1.WAV')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/home/pytorch/anaconda3/lib/python3.6/wave.py", line 499, in open
    return Wave_read(f)
  File "/home/pytorch/anaconda3/lib/python3.6/wave.py", line 163, in __init__
    self.initfp(f)
  File "/home/pytorch/anaconda3/lib/python3.6/wave.py", line 130, in initfp
    raise Error('file does not start with RIFF id')
wave.Error: file does not start with RIFF id

We read into numpy with librosa, write back with soundfile.

import librosa
import soundfile as sf
>>> x,_ = librosa.load('./SA1.WAV', sr=16000)
>>> sf.write('tmp.wav', x, 16000)
>>> wave.open('tmp.wav','r')
<wave.Wave_read object at 0x7fbcb4c8cf28>

回答3:

I have a word-around, I rename the file's suffix to "mp3" and convert it to "wav", then I could be able to read it.

subprocess.call(['ffmpeg', '-i', 'XXX.mp3', 'XXX.wav'])

来源：https://stackoverflow.com/questions/25672289/failed-to-open-file-file-wav-as-a-wav-due-to-file-does-not-start-with-riff-id

标签

python

mime-types

wav

riff