How to do submodule sparse-checkout with Git?

问题

There are a lot of articles and SO questions about sparse-checkout. Unfortunately I did not find concrete examples. I would like to get this following example work:

Create a submodule

cd ~
mkdir sub && cd $_
git init 
mkdir foo && touch $_/foo
mkdir bar && touch $_/bar
git add .
git commit -am "Initial commit"

Create a project

cd ~
mkdir project && cd $_
git init
git submodule add ../sub sub
git config -f .gitmodules submodule.sub.shallow true
git config -f .gitmodules submodule.sub.sparsecheckout true
echo foo/* > .git/modules/sub/info/sparse-checkout
git commit -am "Initial commit"
git submodule update
cd sub
git checkout .

A this point I am expecting sub folder to only contain foo/foo not bar. Unfortunately it doesn't work:

$ ls
bar/ foo/

How can I make it work?

回答1:

git submodule add itself checks out the submodule.

What succeeded for me was:

git init
# I did not find a way to add submodule in 1 step without checking out
git clone --depth=1 --no-checkout ../sub sub
git submodule add ../sub sub
git submodule absorbgitdirs
# note there is no "submodule.sub.sparsecheckout" key
git -C sub config core.sparseCheckout true
# note quoted wildcards to avoid their expansion by shell
echo 'foo/*' >>.git/modules/sub/info/sparse-checkout
git submodule update --force --checkout sub

来源：https://stackoverflow.com/questions/45688121/how-to-do-submodule-sparse-checkout-with-git