Modify regex to match dates with ordinals “st”, “nd”, “rd”, “th”

与世无争的帅哥 提交于 2019-12-07 07:54:28

This will depend on your use case, but in the interest of pragmatism, you might do well to just match anything matching:
(1) any month name or abbreviation;
(2) whitespace;
(3) any one or two digits;
(4) whitespace;
(5) any st,nd,rd,th;
(6) whitespace OR comma + optional whitespace;
(7) any four digits;

I'm not sure what you're matching in, but if I had Jan 35nd,3001, I think I'd rather capture it now and invalidate it later than to just skip over it right at the get-go.

Also, depending on your data set, consider case sensitivity issues and common international English variants, like 1 Jan 2004 or 1st Jan, 2004 or January, 2004 etc.

line breaks added

^(?:j(?:an(?:uary)?|un(?:e)?|ul(?:y)?)?|feb(?:ruary)?|ma(?:r(?:ch)?|y)
|a(?:pr(?:il)?|ug(?:ust)?)|sep(?:t|tember)?|oct(?:ober)?|(?:nov|dec)(?:ember)?)  
\s+\d{1,2}(?:st|nd|rd|th)?(?:\s+|,\s*)\d{4}\b

Even more pragmatic (and readable), unless you have a very bizarre dataset, is to allow anything after the common prefixes:

(?:jan|feb|mar|apr|may|jun|jul|aug|sep|oct|nov|dec)[a-z]*?\s+\d{1,2}(?:[a-z]{2})?(?:\s+|,\s*)\d{4}\b

Would this match octagenarianism 99xx, 0000 ? Yes. Is that likely to be an issue? I doubt it.

That regex is doing waaaaay too much. You'd be much better off using your language's equivalent of strptime(). However, the regex below will match ordinals:

^(?:(((Jan(uary)?|Ma(r(ch)?|y)|Jul(y)?|Aug(ust)?|Oct(ober)?|Dec(ember)?)\ 31(st)?)|((Jan(uary)?|Ma(r(ch)?|y)|Apr(il)?|Ju((ly?)|(ne?))|Aug(ust)?|Oct(ober)?|(Sept|Nov|Dec)(ember)?)\ (0?[1-9]|([12]\d)|30))(st|nd|rd|th)?|(Feb(ruary)?\ (0?[1-9]|1\d|2[0-8]|(29(th)?(?=,\ ((1[6-9]|[2-9]\d)(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00)))))(st|nd|rd|th)?))\,\ ((1[6-9]|[2-9]\d)\d{2}))

Note that it will also match things like "20nd" but the likelihood of encountering that in real data is way too low to bother caring in most cases.

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