问题
If I were to wanted to parameterize creating an object, I could of course make a function which called new on a particular class and passed out a pointer. I am wondering if it's possible to skip that step and pass a function pointer to the new operator itself.
回答1:
boost::lambda provides function wrappers for new and delete. These can be used to easily convert an new call into a function object.
回答2:
operator new (as well as the other flavours) takes care of allocating memory but does not construct objects. In fact its return type is void*. What constructs an object is a new expression, which is part of the language and not a function. So it's not possible to form a pointer or reference to it; it's as meaningless as forming a reference to return.
来源：https://stackoverflow.com/questions/6604911/is-it-possible-to-create-a-function-pointer-to-the-a-functions-new-operator-c