What does (int (*)[])var1 stand for?

问题

I found this example code and I tried to google what (int (*)[])var1 could stand for, but I got no usefull results.

#include <unistd.h>
#include <stdlib.h>

int i(int n,int m,int var1[n][m]) {
    return var1[0][0];
}

int example() {
    int *var1 = malloc(100);
    return i(10,10,(int (*)[])var1);
} 

Normally I work with VLAs in C99 so I am used to:

#include <unistd.h>
#include <stdlib.h>

int i(int n,int m,int var1[n][m]) {
    return var1[0][0];
}

int example() {
    int var1[10][10];
    return i(10,10,var1);
} 

Thanks!

回答1:

It means "cast var1 into pointer to array of int".

回答2:

It's a typecast to a pointer that points to an array of int.

回答3:

(int (*)[]) is a pointer to an array of ints. Equivalent to the int[n][m] function argument.

This is a common idiom in C: first do a malloc to reserve memory, then cast it to the desired type.

来源：https://stackoverflow.com/questions/2972978/what-does-int-var1-stand-for