问题
I have an ES6 module that exports a React Component class by default, but also exports a plain JS function as a named export. When testing other packages that use this module, I want to mock both the default exported component and named exported function to keep my unit tests pure.
The module looks something like this:
import React, { Component } from 'react';
export default class MyComponent extends Component {
render() {
return <div>Hello</div>
}
}
export function myUtilityFunction() { return 'foo' };
I would like to use the following syntax to mock the exports:
import React from 'react';
import MyComponent, { myUtilityFunction } from './module';
jest.mock('./module');
MyComponent.mockImplementation(() => 'MockComponent');
myUtilityFunction.mockImplementation(() => 'foo');
When I try to use this syntax, however, MyComponent does not appear to be mocked when used within other components. When I try to mock MyComponent like this and render it on its own, it renders out to null.
This behavior is very strange, because if I use the exact same syntax, but both imports are JavaScript functions, the mocking works as expected. See the StackOverflow issue I opened here that confirms that the syntax works when the imports are both functions.
Here is a GitHub repo demoing the problem, as well as several solutions I've tried: https://github.com/zpalexander/jest-enzyme-problem
You can build the repo and run the tests with yarn install && yarn test
Thanks!
回答1:
I think the issue is that the ShallowWrapper class's getElement method needs to be passed a class that contains a render method. To do that, your MyComponent.mockImplementation needs to more fully mock a class constructor.
For details on how to mock a class constructor, see the Jest documentation starting at "mockImplementation can also be used to mock class constructors:" https://facebook.github.io/jest/docs/en/mock-function-api.html#mockfnmockimplementationfn
Using the Jest documentation as a model, we can mock the MyComponent class constructor and make it shallow renderable by enzyme like this:
MyComponent.mockImplementation(() => {
return {
render: () => <div>MockComponent</div>
};
});
Now when getElement goes looking for a render method it will find it.
Here's a gist that implements this change on the App.mockImplementation.test.js file from your repo: https://gist.github.com/timothyjellison/a9c9c2fdfb0b30aab5698dd92e901b24
回答2:
The other solution didn't work for me. This is how I did:
jest.mock('./module', () => ({
__esModule: true,
myUtilityFunction: 'myUtilityFunction',
default: 'MyComponent'
}));
Another way to do it:
jest.unmock('../src/dependency');
const myModule = require('../src/dependency');
myModule.utilityFunction = 'your mock'
来源:https://stackoverflow.com/questions/48831701/jest-how-to-mock-default-export-component-when-same-module-also-has-named-expor