问题
I'm developing a school database system in Django 1.5, and was planning on having a number of different user types (Student, Staff, Parent) which subclass AbstractUser (actually, another abstract subclass of AbstractUser). I was just attempting to add an externally developed app to my system, which uses User in a ForeignKey for some of its models, however, this fails as my user type is not a 'User' instance. I can't set the apps models to use AbstractUser as one can't use abstract classes for Foreign Keys. I was then considering adding to my settings.py AUTH_USER_MODEL = 'myapp.MyUser'
and using settings.AUTH_USER_MODEL in place of User for the ForeignKey in the app. However, I have 3 different user types, so can't do this either.
An earlier prototype used Django 1.4, which did not support custom User models, hence had a reference to a User instead, but this required an extra join for every query, which was leading to quite complex queries. Is this the only way I can go forward with this, or is there another solution?
回答1:
I have successfully used the following solution:
1. Create SchoolUser
class in models.py - this will be your AUTH_USER_MODEL
class
TYPES = (('Student', 'Student'), ('Staff', 'Staff'), ('Parent', 'Parent'), )
class SchoolUser(AbstractUser):
type = models.CharField(max_length=10, choices=TYPES, default='Student')
2. Create users.py file and put whole users logic there. Have one abstract class that all others inherit from and which will implement the factory method:
class UserManager(object):
def __init__(self, user):
self.user = user
@classmethod
def factory(cls, user):
"""
Dynamically creates user object
"""
if cls.__name__.startswith(user.type): # Children class naming convention is important
return cls(user)
for sub_cls in cls.__subclasses__():
result = sub_cls.factory(user)
if result is not None:
return result
Sample children classes (also go to users.py file):
class StudentUser(UserManager):
def do_something(self):
pass
class StaffUser(UserManager):
def do_something(self):
pass
class ParentUser(UserManager):
def do_something(self):
pass
Views is where the magic happens ;)
def my_view(request):
school_user = UserManager.factory(request.user)
if school_user.do_something: # each class can have different behaviour
This way you don't need to know, which type of user it is, just implement your logic.
I hope this is clear enough, if not let me know!
来源:https://stackoverflow.com/questions/16682042/subclassing-abstractuser-in-django-for-two-types-of-users