I am trying to duplicate the slider found here.
I have a file index.php
and the code is as follows:
Head:
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.9.2/jquery-ui.js"></script>
<style type="text/css">
.top {
margin: 0px;
padding: 0px;
height: 500px;
width: 500px;
}
.testing {
margin-left: auto;
margin-right: auto;
margin-top: 200px;
margin-bottom: 200px;
padding: 0px;
height: 100px;
width: 100px;
background: red;
border: 1px solid #000;
}
</style>
</head>
Body:
<body>
<div class="top">
<div class="testing"></div>
</div>
<p>a: <span id="a">0</span>
<div id="a_slider"></div>
</p>
</body>
JavaScript:
<script>
$("#a_slider").slider({
orientation: "horizontal",
range: false,
min: 0,
max: 1,
value: 0,
step: .01,
animate: true,
slide: function (event, ui) {
$("#a_field").val(ui.value);
$("#a").text(ui.value);
}
});
</script>
But it is not working! I can only guess that the jqueryui
link in the head is incorrect, but I'm pretty sure it's the same one as in the fiddle above.
IF you supply a fiddle in your solution, please use external resources so I can find the appropriate files. The simple class and ID names are purely for testing purposes.
Entire HTML:
<html>
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.9.2/jquery-ui.js"></script>
<style type="text/css">
.top {
margin: 0px;
padding: 0px;
height: 500px;
width: 500px;
}
.testing {
margin-left: auto;
margin-right: auto;
margin-top: 200px;
margin-bottom: 200px;
padding: 0px;
height: 100px;
width: 100px;
background: red;
border: 1px solid #000;
}
</style>
</head>
<body>
<div class="top">
<div class="testing"></div>
</div>
<p>a: <span id="a">0</span>
<div id="a_slider"></div>
</p>
</body>
<script>
$("#a_slider").slider({
orientation: "horizontal",
range: false,
min: 0,
max: 1,
value: 0,
step: .01,
animate: true,
slide: function (event, ui) {
$("#a_field").val(ui.value);
$("#a").text(ui.value);
}
});
</script>
</html>
Thank you.
EDIT
I've tried using http://code.jquery.com/ui/1.10.4/jquery-ui.min.js
, but also no dice. Below is a screen shot of what shows up...
Notice in the image that no slider shows up.
Here is the Working Fiddle
Try loading jQuery UI properly:
<link rel="stylesheet" href="https://code.jquery.com/ui/1.9.2/themes/base/jquery-ui.css">
<script src="https://code.jquery.com/jquery-1.9.1.js"></script>
<script src="https://code.jquery.com/ui/1.9.2/jquery-ui.js"></script>
$("#a_slider").slider({
orientation: "horizontal",
range: false,
min: 0,
max: 1,
value: 0,
step: .01,
animate: true,
slide: function (event, ui) {
$("#a_field").val(ui.value);
$("#a").text(ui.value);
}
});
You have to include the jQuery UI stylesheet too:
<link href="css/ui-lightness/jquery-ui-1.9.2.custom.css" rel="stylesheet">
Then it will work.
Just add the jQuery UI touch after jQuery ui:
<script src="http://code.jquery.com/jquery-1.10.2.js"></script>
<script src="http://code.jquery.com/ui/1.11.2/jquery-ui.js"></script>
<script src="https://raw.githubusercontent.com/furf/jquery-ui-touch-punch/master/jquery.ui.touch-punch.js"></script>
来源:https://stackoverflow.com/questions/21467239/jquery-slider-not-working