I have two strings as follows :
STRING1 : 011011110011000
STRING2 : 011001000001000
EXPECTED OUTPUT : 000010110010000
However, when i try to XOR them(bit-wise) using the following code, the output is blank. Code:
for(int i = 0; i<15; i++)
{
final_key[i] = STRING1[i] ^ STRING2[i];
cout<<" XOR = "<<final_key[i];
}
Any help would be appreciated.
You are trying to XOR 2 char
at a time. Try instead:
final_key[i] = ((STRING1[i]-'0') ^ (STRING2[i]-'0')) + '0';
Explanation
Refer to here for ASCII values.
The ASCII value for '0'
is 48 and the ASCII value of '1'
is 49. 48 ^ 49
is 1, 48 ^ 48
and 49 ^ 49
is 0. These would return a value of 0 or 1 to a char
, which would stand for either a EOF
char (if it is 0) or a SOH
char (if it is one), neither of which are output correctly.
Thus you would want to convert each char
into a bit (0 or 1) before conducting the XOR operation. Thus you can subtract '0'
from each char
to get the numrical value of the digit, conduct the XOR operation, then add back '0'
to get a proper output
c++ has std::bitset<>
#incude <string>
#incude <bitset>
#incude <iostream>
int main()
{
std::string s1 = "010101010101010101";
std::string s2 = "101010101000001111";
auto result = std::bitset<32>(s1) ^ std::bitset<32>(s2);
std::cout << result << std::endl;
}
The ASCII values of the characters '0' and '1' are 48 and 49. To apply an XOR on two characters a,b ∈ { '0', '1' } you may use:
char result = std::abs(a - b) + '0';
string strings_xor(string s, string t) {
string res = "";
for(int i = 0; i < s.size(); i++) {
if(s[i] == t[i])
res += '0';
else
res += '1';
}
return res;
}
hope this helps.
You are Xoring characters.That works but you are storing the result as it is without converting the result into character.
string s1="011011110011000";
string s2="011001000001000";
char final_key[15];
for(int i = 0; i<15; i++)
{
final_key[i] = (s1[i] ^ s2[i])+'0'; //paranthesis is important
cout<<final_key[i];
}
You could also check whether s1[i]
is not equal to s2[i]
, then result is 1
final_key[i]=(s1[i]!=s2[i]?'1':'0');
来源:https://stackoverflow.com/questions/39394285/xor-two-binary-strings-c