I have a one to many relationship between User and LinkedAccount, a User can have several linked accounts.
I have no problem in loading a LinkedAccount and it's User by doing: LinkedAccount(id, provider_user_id, salt, provider_id, auth_method, avatar_url, User.findBy(user))
in the parser.
What I can't figure out is how load a user with it's LinkedAccounts. I guess I need to make the user aware of the LinkedAccounts.. but how?
I would like to this to get rid of one extra sql call to the db everytime I want to find if the user have a linked account of the given type. Currently I do like this:
def findLinkedAccountByUserAndProvider(userId: Pk[Long], providerId : String) = {
DB.withConnection {
implicit connection =>
SQL("select * from linked_account la where la.user_id = {userId} and la.provider_id = {providerId}")
.on("userId" -> userId, "providerId" -> providerId).as(LinkedAccount.simple.singleOpt)
}
}
Or will this cause a problem when User is aware of it's LinkedAccounts and LinkedAccount is aware of it's user?
User:
case class User(id: Pk[Long] = NotAssigned,
firstName: String,
lastName: String,
email: String,
emailValidated: Boolean,
lastLogin: DateTime,
created: DateTime,
modified: DateTime,
active: Boolean)
object User {
val simple = {
get[Pk[Long]]("id") ~
get[String]("first_name") ~
get[String]("last_name") ~
get[String]("email") ~
get[Boolean]("email_validated") ~
get[DateTime]("last_login") ~
get[DateTime]("created") ~
get[DateTime]("modified") ~
get[Boolean]("active") map {
case id ~ first_name ~ last_name ~ email ~ email_validated ~ last_login ~ created ~ modified ~ active =>
User(id, first_name, last_name, email, email_validated, last_login, created, modified, active)
}
}
}
LinkedAccount:
case class LinkedAccount(id: Pk[Long] = NotAssigned,
providerUserId: String,
salt: Option[String],
providerId: String,
authMethod: Option[String],
avatarUrl: Option[String],
user: User
)
object LinkedAccount {
val simple = {
get[Pk[Long]]("id") ~
get[String]("provider_user_id") ~
get[Option[String]]("salt") ~
get[String]("provider_id") ~
get[Option[String]]("auth_method") ~
get[Option[String]]("avatar_url") ~
get[Pk[Long]]("user_id") map {
case id ~ provider_user_id ~ salt ~ provider_id ~ auth_method ~ avatar_url ~ user =>
LinkedAccount(id, provider_user_id, salt, provider_id, auth_method, avatar_url, User.findBy(user))
}
}
}
Since I got no answer I will provide my own:
In the case class I define:
case class User(id: Pk[Long] = NotAssigned,
firstName: String,
lastName: String,
email: String,
emailValidated: Boolean,
lastLogin: DateTime,
created: DateTime,
modified: DateTime,
active: Boolean) {
lazy val linkedAccounts: Seq[LinkedAccount] = DB.withConnection("test") { implicit connection =>
SQL(
"""
select * from linked_account la
join users on la.user_id = users.id
where la.id = {id}
"""
).on(
'id -> id
).as(LinkedAccount.simple *)
}
}
And then get the accounts by:
val linkedAccounts = user.linkedAccounts
Found this here
来源:https://stackoverflow.com/questions/15427469/play2-and-anorm-how-do-i-make-the-one-in-a-one-to-many-relationship-aware-of-it